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Deffense [45]
3 years ago
13

Can anyone help with A ? it’s the pythagorean theorem

Mathematics
1 answer:
ANTONII [103]3 years ago
5 0

Answer:

The sides are <u>not</u> a right triangle

Step-by-step explanation:

      The Pythagorean theorem states that a² + b² = c²

-> a and b are the legs

-> c is the hypotenuse

      We can plug the values that we have in, and see if it will solve correctly.

a² + b² = c²

11² + 5² = 13²

121 + 25 = 169

146 ≠ 169

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Readme [11.4K]

Answer:

a. 36

b. 4

c. -11

d. 2

e. -20

Step-by-step explanation:

20 + 16 = 36

20 + (-16)

20 - 16 = 4

5 + (-16)

5 - 16 = -11

-9 + 11

11 - 9 = 2

-9 + (-11)

-9 - 11 = -20

4 0
3 years ago
Help please!!!!!!!!!!!!!!!
tensa zangetsu [6.8K]

Answer:

  1. y=8x-3
  2. y=-2x-1
  3. y=-x-1
  4. y=4x+5
  5. y=3
  6. y=7x+0 or y=7x
  7. y=10x+4
  8. y=-6x+9

the equation for the graph:

y=2x-2

use the y-intercept ((0,-2))

and the for the slope you do y1-y2/x1-x2

0-(-2)/1-0= 2

5 0
3 years ago
HELP PLZZ will give brainliest &lt;3
melisa1 [442]

Answer:

0

1

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

\dfrac{a}{\sin A} = \dfrac{b}{\sin B}

\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}

\dfrac{1}{0.5} = \dfrac{4}{\sin B}

\sin B = 2

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

\dfrac{b}{\sin B} = \dfrac{c}{\sin C}

\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}

\sin C = \dfrac{8.9\sin 63^\circ}{10}

C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}

C \approx 52.5^\circ

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

3 0
4 years ago
What number can be add to <br><img src="https://tex.z-dn.net/?f=%20%7B9x%7D%5E%7B2%7D%20%20%2B%2024x" id="TexFormula1" title=" {
4vir4ik [10]

The required number will be 16

the expression will be like :

  • 9 {x}^{2}  + 24x + 16

  • (3x) {}^{2}  + (2 \times 3x \times 4) + (4) {}^{2}

  • (3x + 4) {}^{2}

hope it helps you cap !!

Anti - Venom

5 0
3 years ago
What is the slope of the line that passes through the points (-4,2) and (2,-1)
Anettt [7]

Answer:

1/-2 is the slope

Step-by-step explanation:

\frac{2-(-1)}{-4-2}  = \frac{2+1}{-4-2}  = \frac{3}{-6} = \frac{1}{-2}

8 0
3 years ago
Read 2 more answers
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