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2 years ago

If the exterior angle of a regular polygon is 7.2 degrees, what is the name of that polygon?

Mathematics

1 answer:

kirill [66]2 years ago

8 0

A regular polygon with exterior angle of 7.2 degrees is a 50-gon.

<h3>Regular polygon</h3>

Regular polygon are polygon that are equiangular. This simply means they are polygon with equal angles.

The formula to find the number of sides of a polygon using exterior angle is as follows:

exterior angle = 360 / n

where

n = number of sides

Therefore,

7.2 = 360 / n

cross multiply

7.2n = 360

divide both sides by 7.2

n = 360 / 7.2

n = 50

The polygon has 50 sides. Therefore, it is a 50-gon

learn more on polygon here: brainly.com/question/12105506

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Ratling [72]

Answer:

Step-by-step explanation:

basically 1st you have to multiply the cost of food so 4 times 8

2nd you already know the cost of the room

so 3rd add the values

cost of food=32 dollars

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32 plus 35 =67 $

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3 years ago

|25 POINTS| Suppose you have one pyramid with a base that is 10 meters long and 10 meters wide with a slant that is 15 meters. N

laiz [17]

Answer:

125 meters squared

Step-by-step explanation:

Surface area of initial pyramid:

A= 10²+4*1/2*10*15= 400 m²

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The difference is:

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3 years ago

Simplify 2(x + 6) - 8

Kruka [31]

Answer:

2x+4

Step-by-step explanation:

please give me a brainliest!!

8 0

3 years ago

Read 2 more answers

How do i solve this question

frozen [14]

$\bf \begin{cases}
h(x)=(f\circ g)(x)\\
h(x)=\sqrt{x+5}\\
f(x)=\sqrt{x+2}
\end{cases}\\\\
-------------------------------\\\\
(f\circ g)(x)\implies f[\ g(x)\ ]\implies f[\ g(x)\ ]=\sqrt{g(x)+2}\qquad thus
\\\\\\
\sqrt{g(x)+2}=(f\circ g)(x)=h(x)=\sqrt{x+5}\qquad therefore
\\\\\\
\sqrt{g(x)+2}=\sqrt{x+5}\impliedby \textit{squaring both sides}\\\\\\
g(x)+2=x+5\implies g(x)=x+5-2\implies \boxed{g(x)=x+3}$

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3 years ago

Find an equation for the line tangent to the circle x^2 +y^2=25 at the point (3, -4)

Lostsunrise [7]

Hello :
the center of this cercle is : O( 0, 0)
calculate the slope m of the line : OA .. A (3,-4)
m= (yA - yO) / (xA- xO)
m = (-4-0)/(3-0)
m= -4/3
if : k the slope of the tangent : k×m = -1 (the tangent perpendiclar of : OA)
k× (-4/3) = -1
k = 3/4
an equation of this tangent is : y - (-4) = (3/4)(x-3)

7 0

3 years ago