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dezoksy [38]
2 years ago
15

If the exterior angle of a regular polygon is 7.2 degrees, what is the name of that polygon?

Mathematics
1 answer:
kirill [66]2 years ago
8 0

A regular polygon with exterior angle of 7.2 degrees is a 50-gon.

<h3>Regular polygon</h3>

Regular polygon are polygon that are equiangular. This simply means they are polygon with equal angles.

The formula to find the number of sides of a polygon using exterior angle is as follows:

  • exterior angle = 360 / n

where

n = number of sides

Therefore,

7.2 = 360 / n

cross multiply

7.2n = 360

divide both sides by 7.2

n = 360 / 7.2

n = 50

The polygon has 50 sides. Therefore, it is a 50-gon

learn more on polygon here: brainly.com/question/12105506

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Step-by-step explanation:

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astra-53 [7]

Answer:

a. a = 1, b = -5, c = -14

b. a = 1, b = -6, c = 9

c. a = -1, b = -1, c = -3

d. a = 1, b = 0, c = -1

e. a = 1, b = 0, c = -3

Step-by-step explanation:

a. x-ints at 7 and -2

this means that our quadratic equation must factor to:

(x-7)(x+2) = 0

FOIL:

x^2 + 2x - 7x - 14 = 0

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b. one x-int at 3

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FOIL:

x^2 - 3x - 3x +9 = 0

Simplify:

x^2 - 6x + 9 = 0

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c. no x-int and negative y must be less than 0

This means that our vertex must be below the x-axis and our parabola must point down

There are many equations for this, but one could be:

-x^2-x-3=0

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d. one positive x-int, one negative x-int

We can use any x-intercepts, so let's just use -1 and 1

The equation will factor to:

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This is a perfect square

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x^2-1=0

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e. x-int at \sqrt{3} , -\sqrt{3}

our equation will factor to:

(x+\sqrt{3} )(x-\sqrt{3)} =0

This is also a perfect square

FOIL and you will get:

x^2 - 3 = 0

a = 1, b = 0, c = -3

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2 years ago
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leonid [27]

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Step-by-step explanation:

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Answer:

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