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3 years ago

I will give brainliest!!!!!

Mathematics

2 answers:

user100 [1]3 years ago

4 0

The sum of their age is "s" years? Please fix the typo. Then I might be able to help :D

jolli1 [7]3 years ago

4 0

If you give us the sum of their age, we will help you! :D

You might be interested in

Mary is 2 times older than Bob and Bob is 5 years older than Sally. Sally is 10 years old how old is Bob

s344n2d4d5 [400]

Answer:

Bob is 15 years old.

Step-by-step explanation:

If Sally is 10 years old and Bob is five years older than Sally then we just need to add 10+5=15.

Hope this helps!!

8 0

3 years ago

Which equation is satisfied by all three of the plotted points?

Elan Coil [88]

Answer:

Use desmos graphing calculator plug in your equations and see which one has all points.You can use desmos for a bunch of stuff too

Step-by-step explanation:its C though

8 0

3 years ago

Read 2 more answers

There are 130 people in a sport centre.

Mashcka [7]

Answer:

Step-by-step explanation:

Using set notation to answer the question. let:

n(U) be the total people in a sport centre =130

n(G) be number of people that use the gym. = 76

n(P) be number of people that use the swimming pool. = 60

n(T) be number of people that use the track = 32

n(G∩P) be number of people that uses the gym and the pool = 23

n(P∩T) be number of people that uses the pool and the track = 8

n(G∩T) be number of people that uses the gym and the track = 320

n(G∩P∩T) be number of people that uses all three facilities = 6

Using the relationship below;

n(U)= n(GUPUT)+n(GUPUT)'

where n(GUPUT)' is the number of people that doesn't use any facility.

Before we can get that, we need to know n(GUPUT) using the formula;

n(GUPUT) = n(G) + n(P)+n(T)-n(G∩P)-n(P∩T)-n(G∩T)+n(G∩P∩T)

n(GUPUT) = 76+60+32-23-8-20+6

n(GUPUT) = 123

n(GUPUT)' = n(U)- n(GUPUT)

n(GUPUT)' = 130 - 123

n(GUPUT)' = 7

This means that 7 person doesn't use any facility.

Probability that a person selected at random doesn't use any facility = n(GUPUT)' /n(U) = 7/130

3 0

3 years ago

Jeff has $6000 in a savings account, has $15000 in investments, he owned a guitar worth $1000, he has $17000 left to pay on his

Law Incorporation [45]

Answer:

$200

Step-by-step explanation:

To find Jeff's net worth, we will deduct all his debts (liabilities) from his assets (his properties).

ASSETS

Savings Account - $6000

Investments - $15000

Guitar - $1000

TOTAL - $22000

LIABILITIES

Student loans - $17000

Credit Card Debt - $1200

Outstanding car payment - $3600

TOTAL - $21800

NET WORTH = Assets - Liabilities

NW = $22000 - $21800

NW = $200

His net worth is $200.

4 0

3 years ago

Sally Sue had spent all day preparing for the prom. All the glitz and the glamour of the evening fell apart as she stepped out o

Nuetrik [128]

We have the function

$p(t)=550(1-e^{-0.039t})$

Therefore we want to determine when we have

$p(t_0)=550$

It means that the term

$e^{-0.039t}$

Must go to zero, then let's forget the rest of the function for a sec and focus only on this term

$e^{-0.039t}\rightarrow0$

But for which value of t? When we have a decreasing exponential, it's interesting to input values that are multiples of the exponential coefficient, if we have 0.039 in the exponential, let's define that

$\alpha=\frac{1}{0.039}$

The inverse of the number, but why do that? look what happens when we do t = α

$e^{-0.039t}\Rightarrow e^{-0.039\alpha}\Rightarrow e^{-1}=\frac{1}{e}$

And when t = 2α

$e^{-0.039t}\Rightarrow e^{-0.039\cdot2\alpha}\Rightarrow e^{-2}=\frac{1}{e^2}$

We can write it in terms of e only.

And we can find for which value of α we have a small value that satisfies

$e^{-0.039t}\approx0$

Only using powers of e

Let's write some inverse powers of e:

$\begin{gathered} \frac{1}{e}=0.368 \\ \\ \frac{1}{e^2}=0.135 \\ \\ \frac{1}{e^3}=0.05 \\ \\ \frac{1}{e^4}=0.02 \\ \\ \frac{1}{e^5}=0.006 \end{gathered}$

See that at t = 5α we have a small value already, then if we input p(5α) we can get

$\begin{gathered} p(5\alpha)=550(1-e^{-0.039\cdot5\alpha}) \\ \\ p(5\alpha)=550(1-0.006) \\ \\ p(5\alpha)=550(1-0.006) \\ \\ p(5\alpha)=550\cdot0.994 \\ \\ p(5\alpha)\approx547 \end{gathered}$

That's already very close to 550, if we want a better approximation we can use t = 8α, which will result in 549.81, which is basically 550.

Therefore, we can use t = 5α and say that 3 people are not important for our case, and say that it's basically 550, or use t = 8α and get a very close value.

In both cases, the decimal answers would be

$\begin{gathered} 5\alpha=\frac{5}{0.039}=128.2\text{ minutes (good approx)} \\ \\ 8\alpha=\frac{8}{0.039}=205.13\text{ minutes (even better approx)} \end{gathered}$

7 0

1 year ago