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Umnica [9.8K]
2 years ago
8

Quadratic function with (-2,4) as the vertex and passes through (-4,-4)

Mathematics
2 answers:
BARSIC [14]2 years ago
8 0
-2x^2 + 8 because if you turn it into vertex form and determine
ollegr [7]2 years ago
3 0

Answer:

f(x)=-2x^2-8x-4

Step-by-step explanation:

Vertex form of quadratic function:  f(x)=a(x-h)^2+k

where (h,k) is the vertex

Given:

  • vertex = (-2, 4)

\implies f(x)=a(x+2)^2+4

Given:

  • point on curve = (-4, -4)

\implies f(-4)=-4\\\\\implies a(-4+2)^2+4=-4\\\\\implies a(-2)^2=-4-4\\\\\implies 4a=-8\\\\\implies a = -2

Therefore,

f(x)=-2(x+2)^2+4\\\\\implies f(x)=-2(x^2+4x+4)+4\\\\\implies f(x)=-2x^2-8x-8+4\\\\\implies f(x)=-2x^2-8x-4

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Vesna [10]

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3 years ago
Determine if the sequence is geometric. If it is, find the common ratio, the 8th term, and the explicit formula. -2, 6, -18, 54,
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Answer:

Step-by-step explanation:

In a geometric sequence, the consecutive terms differ by a common ratio,r. Considering the given sequence,

r = 6/- 2 = - 18/6 = - 3

Therefore, the sequence is geometric.

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Tn = ar^(n - 1)

Where

a represents the first term of the sequence.

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n represents the number of terms.

From the information given,

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