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Umnica [9.8K]
2 years ago
8

Quadratic function with (-2,4) as the vertex and passes through (-4,-4)

Mathematics
2 answers:
BARSIC [14]2 years ago
8 0
-2x^2 + 8 because if you turn it into vertex form and determine
ollegr [7]2 years ago
3 0

Answer:

f(x)=-2x^2-8x-4

Step-by-step explanation:

Vertex form of quadratic function:  f(x)=a(x-h)^2+k

where (h,k) is the vertex

Given:

  • vertex = (-2, 4)

\implies f(x)=a(x+2)^2+4

Given:

  • point on curve = (-4, -4)

\implies f(-4)=-4\\\\\implies a(-4+2)^2+4=-4\\\\\implies a(-2)^2=-4-4\\\\\implies 4a=-8\\\\\implies a = -2

Therefore,

f(x)=-2(x+2)^2+4\\\\\implies f(x)=-2(x^2+4x+4)+4\\\\\implies f(x)=-2x^2-8x-8+4\\\\\implies f(x)=-2x^2-8x-4

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Which expression is a difference of cubes?
GREYUIT [131]

Answer:

64c15 - 0.027.

Step-by-step explanation:

That would be 64c15 - 0.027

= 4c^5 - 0.3.

3 0
3 years ago
What is the slope of the line whose equation is y - = 0? slope = slope = - slope = 0
sasho [114]

Answer:

the slope is 0

Step-by-step explanation:

7 0
3 years ago
Goals scored by a hockey team in successive matches are 5,7,4,2,4,0,5,5 and 3. What is the number of goals, the team must score
Stels [109]

Answer:

5

Step-by-step explanation:

Total goals /total no. of matches = 4

5+7+4+2+4+0+5+5+3+x / 10 = 4

35 + x = 4 × 10

x = 40 - 35

x = 5

So, the team must score 5 inorder to get the average of 4 goals per match.

6 0
2 years ago
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
Explain how to use multiplication to find
Sindrei [870]

A fraction x/y is a ratio between two numbers x and y.

The ratio is preserved if both x and y are scaled up or down by the same number n.

This means you can obtain any fraction equivalent to x/y by multiplying both x and y by n, i.e. (n*x)/(n*y).

Then we have 1/4 = (2*1)/(2*4) = 2/8, for example.

5 0
3 years ago
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