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GarryVolchara [31]
2 years ago
12

Question 4 of 10

Mathematics
2 answers:
Snezhnost [94]2 years ago
7 0

✴<u>Given:</u>

↪Purchase price = $190,000

↪Appraisal fee = $450

↪Processing fee = $575

↪Title fee = $600

✴<u>Lets , find total closing costs :</u>

\small\bold\red{[Total \:  closing \:  costs = 2 \% \: of  \: the \:  purchase \:  price + appraisal  \: fee + processing  \: fee + title  \: fee]}

↪ $190000 × 0.02 + $450 + $575 + $600

↪ $3800 + $450 + $575 + $600

↪ $5425

Answer :- \small\bold\pink{C.) 5425}

konstantin123 [22]2 years ago
3 0

Answer:

C)  $5425

Step-by-step explanation:

Total closing costs = 2% of the purchase price + appraisal fee + processing fee + title fee

Given:

  • purchase price = $190,000
  • appraisal fee = $450
  • processing fee = $575
  • title fee = $600

Total closing costs = $190000 x 0.02 + $450 + $575 + $600

                               = $3800 + $450 + $575 + $600

                               = $5425

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taxes
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explanation
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4 years ago
A man bought a horse and carriage for $500 paying three times as much for the carriage as for the horse how much did each cost
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PilotLPTM [1.2K]

<u>Answer:</u>

12 units

<u>Step-by-step explanation:</u>

We are given these two points, (-7,-6) and (5,-6), and we are to find the distance between them.

We know the formula for finding the distance between two points:

<em>Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}</em>

So putting in the values of the given coordinates in the above formula to get:

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Answer:

(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

Step-by-step explanation:

(a) To find the solutions of the following system of equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. you must:

Multiply 2x-3y=3 by 2:

\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}

Subtract the equations

4x-6y=3\\-\\4x-6y=6\\------\\0=-3

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. you must:

Isolate x for 4x-6y=10

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Substitute x=\frac{5+3y}{2} into the second equation

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The system has many solutions.

Isolate y for 4x-6y=10

y=\frac{2x}{3}-\frac{5}{3}

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