93/4
9/4=2r1
13/4=4r1
10/4=2r2
20/5=4
=23.25
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
#SPJ1
Answer:
Leslie determined that the system of equations below has infinitely many solutions. Is she correct?
x=4y-4
2x-8y=-24
A.Yes, Leslie is correct.
B. No, the solution is (-8,-24)
C. No, the solution is (0,-16)
<u>D. No, the system of equations has no solution. </u>
Step-by-step explanation:
you have to solve they as a pair of simultaneous equations and their is no solutions
if you need a more detailed explanation post the question again and i will write a detailed explanation
plz mark as brainliest
Answer:
50?
Step-by-step explanation:
I said 50 because there were 60 na butterflies so there was probably 50.
I am sorry if this wrong tho
Answer:
x < 3
Step-by-step explanation:
