stranger things A jewellery shop is having a sale.
A bracelet is reduced to £240.
a) What is the original price?
A ring is reduced to £840.
This is 40% of the original price.
b) Work out the original price of this ring.A jewellery shop is having a sale.
A bracelet is reduced to £240.
a) What is the original price?
% of the original price.
b) Work out the original price of this ring.A jewellery shop is having a sale.
A bracelet is reduced to £240.
a) What is the original price?
A ring is reduced to £840.
This is 40% of the original price.
b) Work out the original price of this ring.A jewellery shop is having a sale.
A brace
A ring is reduced to £840.
This is 40% of the original price.
b) Work out the original price of this ring. yeey this is important
Answer:
58%
Step-by-step explanation:
This is because you need to set up the equation _ % of _ is _ and then plug in numbers. _% of 377 is 217 is the final equation. Then divide 217 by 377 which is 0.57559681697. Then you round to the nearest hundredth to get 58%
The pool can hold 65.84 ft³ of water
<u>Explanation:</u>
Given:
Shape of pool = octagonal
Base area of the pool = 22 ft²
Depth of the pool = 3 feet
Volume, V = ?
We know:
Area of octagon = 2 ( 1 + √2) a²
22 ft² = 2 ( 1 + √2 ) a²

a² = 
a² = 4.55
a = 2.132 ft
Side length of the octagon is 2.132 ft
We know:
Volume of octagon = 

Therefore, the pool can hold 65.84 ft³ of water
The greatest common factor is to h4 and h8 is 4
Answer:
yes
Step-by-step explanation: