Question

Select the correct answer from each drop-down menu. Determine the molecular formula of the compound. A compound is used as a gasoline additive. It has a molecular weight of 60. 10 atomic mass units and an empirical formula of C3H8O. The molecular formula is C H O.

Answer 1

The molecular formula is the representation of the number of atoms and the chemical species of the elements. The molecular formula of the compound is $\rm C_{3}H_{8}O_{1}.$

What is the molecular formula?

A molecular formula depicts the chemical symbols of the atoms of the elements with the subscripts of the number of atoms present in the compound or the molecule.

Given,

Molecular weight of the compound = 60.10 amu

Empirical formula = $\rm C_{3}H_{8}O$

Molar mass of carbon = 12.01 g/mole

Molar mass of oxygen = 15.99 g/mole

Molar mass of hydrogen = 1.01 g/mole

Calculate the empirical mass as:

$\begin{aligned}\text{Empirical mass of}\; \rm C_{3}H_{8}O &= (3 \times 12.01)+(8 \times 1.01)+(1\times 15.99)\\\\&= 60.1\end{aligned}$

The molecular formula can be calculated as,

$\begin{aligned}\text{ Molecular formula} &=\dfrac{\text{Molecular weight}}{\text{Empirical mass}}\\\\&= \dfrac{60.10}{60.1}\\\\&= 1\end{aligned}$

The molecular formula of the compound can be given by multiplying the subscripts of the empirical formula by 1.

Thus, the molecular formula of the compound is $\rm C_{3}H_{8}O_{1}.$

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