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grandymaker [24]
2 years ago
14

Pre-algebra Due urgently Tysm

Mathematics
1 answer:
leva [86]2 years ago
4 0

Answer:

y = 4 / x = 2

Step-by-step explanation:

Insert x equation for variable x

y = 2(-y+6)

simplify

y= -2y + 12

add 2y to both sides

3y= 12

divide both sides by 3

y = 4

Insert 4 as y in y =2x

4=2x

divide both sides by 2

x=2

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3 years ago
Verify 3/4 + (7/2 + -3/8) = 3/4 + 7/2 + (-3/8)​
Iteru [2.4K]

Answer:

when opening the bracket remember that the value outside the bracket will be used to multiply the value inside the bracket

3 0
3 years ago
What are the dimensions of the pond? Please help.
balu736 [363]

Let's assume

length of box is l

width of box is w

we know that

area of rectangle = length*width

21=l*w...................(1)

now, we are given

fencing length is 20 foot

fencing length will be equal to perimeter

and we know that

perimeter=2(l+w)

so, we get

2(l+w)=20

now, we can solve for l

l=10-w

now, we can plug that in first equation

21=(10-w)*w

now, we can solve for w

10w-w^2=21

w^2-10w+21=0

(w-7)(w-3)=0

w=7 , w=3

now, we can find length

l=10-3=7

or

l=10-7=3

so, option-B..................Answer

8 0
3 years ago
6. Use a one unit multiplier to convert 20 inches to centimeters.
fredd [130]

6. Multiply the given equation by 20

... 20×1 in. = 20×2.54 cm

... 20 in = 50.8 cm

7. Multiply the equation (1 foot = 12 inches) by 25.

... 25×1 ft = 25×12 in

... 25 ft = 300 in

Now, multiply the equation for conversion to cm by 300

... 300×1 in = 300×2.54 cm

... 300 in = 762 cm

Using the transitive property of equality,

... 25 ft = 300 in = 762 cm

... 25 ft = 762 cm

_____

A "unit multiplier" is no doubt explained in your lesson. We assume it is a fraction whose value is 1, but that has different units in numerator and denominator. The equation 1 in = 2.54 cm gives rise to two unit multipliers, depending on which conversion you need or want:

1=\dfrac{1\,\text{in}}{2.54\,\text{cm}}=\dfrac{2.54\,\text{cm}}{1\,\text{in}}

Since you're converting <em>to</em> centimeters, you want the one with <em>cm</em> in the numerator.

(20\,\text{in})\times\dfrac{2.54\,\text{cm}}{1\,\text{in}}=50.8\,\text{cm}

(25\,\text{ft})\times\dfrac{12\,\text{in}}{1\,\text{ft}}\times\dfrac{2.54\,\text{cm}}{1\,\text{in}}=762\,\text{cm}

7 0
4 years ago
What is the area of the shaded region?
andre [41]
We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:

Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:

5^2 = 3^2 + x^2
x = 4

The radius is 4 + 1 cm = 5 cm

So the area of the circle is A = pi*r^2
A = 3.14 * (5)^2 
A = 25pi cm^2

To solve for the area of the shaded region:

Ashaded = Acircle - Atriangles

we need to solve for the area of the triangles:

A = 1/2 *b*h
A = 1/2 *6 * 5
A = 15 cm^2

Atriangles = 2 * 15 
Atriangles = 30 cm^2

Ashaded = 25pi - 30
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8 0
4 years ago
Read 2 more answers
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