Answer:
define f(2) = 11/8
Step-by-step explanation:
To make the graph have a horizontal asymptote at y=3, the coefficient of x^2 in the numerator must be 3 times the coefficient of x^2 in the denominator. That is, a = 3·2 = 6.
In order for there to be a removable discontinuity at x=2, we must have (x-2) a factor of both numerator and denominator. We already know the denominator factors as 2(x-2)(x+2), so we need to find the value of b that makes the numerator have a factor of (x-2).
We can find the required value of "b" using synthetic division. The work shown in the attachment tells us that b=-13 will make division of the numerator by (x-2) have a remainder of zero. So the function is ...
Canceling the factors of (x-2), the simplified function is ...
In order to remove the discontinuity at x=2, the function value must be defined as 11/8.
Answer:
-1152
Step-by-step explanation:
F(1)=-16
F(2)=-28
F(3)=-40
Notice the sequence is decreasing by -12 for every increase in x
You can conclude the function for this sequence is going to be
F(x)=-12x
Plug 96 as X.
F(96)=-1152
Answer:
J 28
Step-by-step explanation:
3x-10 = plug in x for angle C
84-10 = subtract for angle C
74 = C
3x/3 - B/2
For last Angle B always look for 180
74 + 50 = 124
180 - 124 = 56
(2x) = plug in x for angle B
56 = B
x = B/2
x = 3x/3 -B/2
x = 28
Hope this helps