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drek231 [11]
2 years ago
9

Please, someone. Solve for x.

Mathematics
1 answer:
grin007 [14]2 years ago
7 0

Combine the fractions on the left side:

9/(x + 2) + 2/(x - 2) = 1

9 (x - 2) / ((x + 2) (x - 2)) + 2 (x + 2) / ((x + 2) (x - 2)) = 1

(9x - 18) / ((x + 2) (x - 2)) + (2x + 4) / ((x + 2) (x - 2)) = 1

(9x - 18 + 2x + 4) / ((x + 2) (x - 2)) = 1

(11x - 14) / ((x + 2) (x - 2)) = 1

Recall the difference of squares identity,

a² - b² = (a + b) (a - b)

which lets us simplify the denominator on the left side as

(11x - 14) / (x² - 4) = 1

For any real numbers a and b, if a/b = 1, then a = b. This means

11x - 14 = x² - 4

which we can rearrange as

x² - 11x + 10 = 0

Factorize the left side:

(x - 10) (x - 1) = 0

Then

x - 10 = 0   or   x - 1 = 0

x = 10   or   x = 1

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<h2>By angle sum property:</h2>

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If<br> 4x + y = 13<br> - y = 2<br> then y =
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Can anyone help me understand this
bagirrra123 [75]

Answer:

(x, y) = (2, 9)

Step-by-step explanation:

For the triangles to be congruent, the hypotenuses must be the same length:

y = x + 7

and the marked leg must be the same length in each triangle:

y -3 = 4x -2

These are two equations in two unknowns (a "system" of equations) that can be solved in any of the usual ways. Since the first equation gives an expression for y, it is convenient to substitute that into the second equation:

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x +4 = 4x -2 . . . . . . collect terms

x +6 = 4x . . . . . . . . .add 2

6 = 3x . . . . . . . . . . . subtract x

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y = 2 + 7 = 9 . . . . . .substitute for x in the first equation

The values you're looking for are x = 2, y = 9.

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