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drek231 [11]
2 years ago
9

Please, someone. Solve for x.

Mathematics
1 answer:
grin007 [14]2 years ago
7 0

Combine the fractions on the left side:

9/(x + 2) + 2/(x - 2) = 1

9 (x - 2) / ((x + 2) (x - 2)) + 2 (x + 2) / ((x + 2) (x - 2)) = 1

(9x - 18) / ((x + 2) (x - 2)) + (2x + 4) / ((x + 2) (x - 2)) = 1

(9x - 18 + 2x + 4) / ((x + 2) (x - 2)) = 1

(11x - 14) / ((x + 2) (x - 2)) = 1

Recall the difference of squares identity,

a² - b² = (a + b) (a - b)

which lets us simplify the denominator on the left side as

(11x - 14) / (x² - 4) = 1

For any real numbers a and b, if a/b = 1, then a = b. This means

11x - 14 = x² - 4

which we can rearrange as

x² - 11x + 10 = 0

Factorize the left side:

(x - 10) (x - 1) = 0

Then

x - 10 = 0   or   x - 1 = 0

x = 10   or   x = 1

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In 4231, the value of the digit 3 is 110 less than the value of the digit 3 in 3421.

Step-by-step explanation:

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Aidan has 20 ft of fence with which to build a rectangular dog run. What is the maximum area he can enclose? Enter your answer i
irina1246 [14]
<h2>Maximum area is 25 m²</h2>

Explanation:

Let L be the length and W be the width.

Aidan has 20 ft of fence with which to build a rectangular dog run.

         Fencing = 2L + 2W  = 20 ft

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We need to find what is the largest area that can be enclosed.

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