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2 years ago

Gabriella has 3 bottles of water.

Mathematics

1 answer:

Drupady [299]2 years ago

3 0

Answer:

1.5 Liters

Step-by-step explanation:

500ml=0.5L

(0.5L)x3= 1.5L

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3(2x-1) what is the anwser to this

Illusion [34]

Answer:

6x-3

Step-by-step explanation:

3(2x-1)

DISTRIBUTE

3*2x = 6x

3*(-1) = -3

6x-3

6 0

3 years ago

A vase can hold 9 flowers. If a florist had 878 flowers she wanted to put equally into vases, how many flowers would be in the l

zavuch27 [327]

There are 5 flowers in the last vase because you divide 878 by 9 and get 97 and then you have 5 leftover

3 0

3 years ago

Read 2 more answers

What vaule of x makes th question true? 3x+2(x-5)=50 a. 8 b.9 c.11 d.12

Ainat [17]

Hey Tierra7l,

Lets solve your equation together step by step.

$3x+2\left(x-5\right)=50$

$\mathrm{Expand}\:2\left(x-5\right):\quad 2x-10$

$\mathrm{Distribute\:parentheses\:using}:\quad \:a\left(b+c\right)=ab+ac$

$a=2,\:b=x,\:c=-5$

$2\cdot \:x+2\left(-5\right)$

$\mathrm{Apply\:minus-plus\:rules}$

$\:\:+\left(-a\right)=-a$

$2x-2\cdot \:5$

$\mathrm{Multiply\:the\:numbers:}\:2\cdot \:5=10$

$2x-10$

$3x+2x-10=50$

$\mathrm{Add\:similar\:elements:}\:3x+2x=5x$

$5x-10=50$

$\mathrm{Add\:}10\mathrm{\:to\:both\:sides}$

$5x-10+10=50+10$

$\mathrm{Simplify}$

$5x=60$

$\mathrm{Divide\:both\:sides\:by\:}5$

$\dfrac{5x}{5}=\dfrac{60}{5}$

$\mathrm{Simplify}$

$x=12$

Hope this helps,

AnthrαX <span> </span>

4 0

3 years ago

Give me an expression of nine less than a number

kompoz [17]

So if you want it to be 9 less than your number (x) then you would subtract nine.

So it would be:

x - 9.

So if your "number" is 12 then you would substitute x for 12 and it would be 12-9. The answer is 3. So 3 is 9 less than a number (12).

I believe

4 0

3 years ago

A group of dental researchers are testing the effects of acidic drinks on dental crowns. They have five containers of crowns lab

mestny [16]

Answer:

$\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}$