Answer:
D. Axial stress divided by axial strain
Explanation:
Lets take rod is pulled by force P
Stress σ = P/A
We know that
σ = ε E
E= Lets take rod is pulled by force P
Stress σ = P/A
We know that
σ = ε E
σ=Axial stress
ε =Axial Strain = ΔL/L
E= σ/ε
E= Axial stress/Axial Strain
So the modulus of elasticity is the ratio of axial stress to axial strain.
σ=Axial stress
ε =Axial Strain = ΔL/L
E= σ/ε
E= Axial stress/Axial Strain
So the modulus of elasticity is the ratio of axial stress to axial strain.
The option D is correct.
The answer for the problem is explained through this:
The following are the given:
F = 4.719 N, the applied force
a = 33 m/s², the acceleration
Let m = the mass.
By definition of the formula:
F = m*a
Therefore,
m = F/a
= (4.719 N)/(33 m/s²)
= 0.143 kg
Answer: 0.143 kg
Answer:
its energy of an objects motion due to the objects motion. kinetic energy depends on mass and speed
Explanation:
hope that helped
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