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stira [4]
2 years ago
6

Which of the following statements is true about the three quadrilaterals?

Mathematics
1 answer:
OLEGan [10]2 years ago
4 0

Answer:

M and O are similar but not congruent

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(5x+2)(x+1) what is the answer
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5x squared+7x+2. That is the answer
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How do you find the missing length in Pythagorean
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When solving for the missing length, just substitute the values given to their respective places in the equation. If a length of a leg is missing, then substitute the other leg's value to either a or b, then substitute the length of the hypotenuse to c. Then solve. Solving for the hypotenuse's length would be a lot easier than the legs.
3 0
3 years ago
Ok so can you walk me through -8 divided by 1.6
stiks02 [169]
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6 0
3 years ago
Read 2 more answers
Let a = x^2 + 4. Rewrite the following equation in terms of a and set it equal to zero. ( x^2 + 4 )^2 +32 = 12x^2 + 48
Aleks04 [339]
Answer:  In the resulting equation:  " a² - 12a + 32 = 0 " ;
________________________________________________________
  The "coefficient" of the "a" term is:  " - 12" . 
________________________________________________________
  The "constant" is:  " 32 " .
________________________________________________________

Explanation:

________________________________________________________

Let:   "a = x² + 4 " .

Given:  (x² + 4)²  + 32  =  12x² + 48  ; 
______________________________________________________

Factor:  "12x² + 48" into " (x² + 4) " ;

"12x² + 48"  =  12 (x² + 4) " ;
______________________________________________________

Given:    (x² + 4)²  + 32  =  12x² + 48 ; 

rewrite as;  "a² + 32 = 12a " ; 

Subtract "12a" from each side of the equation; 

"a² + 32 - 12a = 12a - 12a ;
 
to get:

" a² - 12a + 32 = 0 " .
___________________________________________________
The coefficient of the "a" term;  that is:

The "coefficient" of " -12a" ;  is:  "- 12" . 

The constant is:  "32<span>" .
</span>___________________________________________________
4 0
3 years ago
9.
RoseWind [281]

Answer:

  C.  I & III

Step-by-step explanation:

I simplifies to ...

  2(6x +15 -5x) +4 = 40

  12x +30 -10x +4 = 40

  2x +34 = 40

__

II simplifies to ...

  40 = 2(15 -x) +4

  40 = 30 -2x +4

  40 = -2x +34 . . . . . . not equivalent to I (sign of x-term is different)

__

III simplifies to ...

  12x +30 -10x +4 = 40

  2x +34 = 40 . . . . . . equivalent to I

___

I & III are equivalent

5 0
3 years ago
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