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ICE Princess25 [194]
3 years ago
14

Let a = x^2 + 4. Rewrite the following equation in terms of a and set it equal to zero. ( x^2 + 4 )^2 +32 = 12x^2 + 48

Mathematics
1 answer:
Aleks04 [339]3 years ago
4 0
Answer:  In the resulting equation:  " a² - 12a + 32 = 0 " ;
________________________________________________________
  The "coefficient" of the "a" term is:  " - 12" . 
________________________________________________________
  The "constant" is:  " 32 " .
________________________________________________________

Explanation:

________________________________________________________

Let:   "a = x² + 4 " .

Given:  (x² + 4)²  + 32  =  12x² + 48  ; 
______________________________________________________

Factor:  "12x² + 48" into " (x² + 4) " ;

"12x² + 48"  =  12 (x² + 4) " ;
______________________________________________________

Given:    (x² + 4)²  + 32  =  12x² + 48 ; 

rewrite as;  "a² + 32 = 12a " ; 

Subtract "12a" from each side of the equation; 

"a² + 32 - 12a = 12a - 12a ;
 
to get:

" a² - 12a + 32 = 0 " .
___________________________________________________
The coefficient of the "a" term;  that is:

The "coefficient" of " -12a" ;  is:  "- 12" . 

The constant is:  "32<span>" .
</span>___________________________________________________
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