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3 years ago

Let a = x^2 + 4. Rewrite the following equation in terms of a and set it equal to zero. ( x^2 + 4 )^2 +32 = 12x^2 + 48

1 answer:

4 0

Answer: In the resulting equation: " a² - 12a + 32 = 0 " ;
________________________________________________________
The "coefficient" of the "a" term is: " - 12" .
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The "constant" is: " 32 " .
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Explanation:
________________________________________________________

Let: "a = x² + 4 " .

Given: (x² + 4)² + 32 = 12x² + 48 ;
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Factor: "12x² + 48" into " (x² + 4) " ;

"12x² + 48" = 12 (x² + 4) " ;
______________________________________________________

Given: (x² + 4)² + 32 = 12x² + 48 ;

rewrite as; "a² + 32 = 12a " ;

Subtract "12a" from each side of the equation;

"a² + 32 - 12a = 12a - 12a ;

to get:

" a² - 12a + 32 = 0 " .
___________________________________________________
The coefficient of the "a" term; that is:

The "coefficient" of " -12a" ; is: "- 12" .

The constant is: "32" .
___________________________________________________

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