Let a = x^2 + 4. Rewrite the following equation in terms of a and set it equal to zero. ( x^2 + 4 )^2 +32 = 12x^2 + 48
1 answer:
Answer: In the resulting equation: " a² - 12a + 32 = 0 " ;________________________________________________________ The "coefficient " of the "a " term is: " - 12 " . ________________________________________________________ The "constant " is: " 32 " .________________________________________________________ Explanation:________________________________________________________ Let: "a = x² + 4 " . Given: ( x² + 4)² + 32 = 12x² + 48 ; ______________________________________________________ Factor: "12x² + 48" into " ( x² + 4) " ; "12x² + 48" = 12 (x² + 4) " ; ______________________________________________________ Given: ( x² + 4)² + 32 = 12x² + 48 ; rewrite as; "a² + 32 = 12a " ; Subtract "12a" from each side of the equation; "a² + 32 - 12a = 12a - 12a ; to get: " a² - 12a + 32 = 0 " .___________________________________________________ The coefficient of the "a " term ; that is: The "coefficient " of " -12a " ; is: "- 12 " . The constant is : "32 <span>" . </span>___________________________________________________
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Step-by-step explanation:
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divide by -1.5: y = 104
substitution to find x:
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Step-by-step explanation:
Since we have given that
We need to find the cos theta between u and w.
As we know the formula for angle between two vectors.
So, it becomes,
Hence, the value of cos theta is -0.352.