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mafiozo [28]
3 years ago
6

9.

Mathematics
1 answer:
RoseWind [281]3 years ago
5 0

Answer:

  C.  I & III

Step-by-step explanation:

I simplifies to ...

  2(6x +15 -5x) +4 = 40

  12x +30 -10x +4 = 40

  2x +34 = 40

__

II simplifies to ...

  40 = 2(15 -x) +4

  40 = 30 -2x +4

  40 = -2x +34 . . . . . . not equivalent to I (sign of x-term is different)

__

III simplifies to ...

  12x +30 -10x +4 = 40

  2x +34 = 40 . . . . . . equivalent to I

___

I & III are equivalent

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Given the function f(x) = 2x, find the value of f−1(32).
Oliga [24]

Answer:

it is -30

Step-by-step explanation:

you would divide both sides by x,then f=2

using PEMDAS we come to -30

5 0
3 years ago
A certain article reported the following observations, listed in increasing order, on drill lifetime (number of holes that a dri
aleksklad [387]

Answer:

Sample mean =119.42

Median = 92

25% trimmed mean = 102.42

10% trimmed mean = 95.69

Step-by-step explanation:

Data in increasing order :

12 13 20 23 31 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249 262 289 323 388 513

Total no. of observations = 50

Sample mean = \frac{\text{Sum of all observations}}{\text{Total number of observations}}

= \frac{5971}{50} = 119.42

Median: Since we have even number of observation

Median = \frac{1}{2}({25\text{th term} + 26\text{th term}) = \frac{91+93}{2} = 92

10% Trimmed Mean: We remove 5 values from each side

Trimmed set = 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249

Trimmed mean =  \frac{\text{Sum of Trimmed Set}}{\text{Total number of observations}} = \frac{4097}{40} = 102.42

25% Trimmed Mean: We remove 12 values from each side.

Trimmed set =  66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141

Trimmed mean =  \frac{\text{Sum of Trimmed Set}}{\text{Total number of observations}} = \frac{2488}{26} = 95.69

6 0
3 years ago
Point C is twice as close to point B as it is to point A. If point A is at -30 and point B is at 30, what are two possible value
arsen [322]

different between A and B

=30-(-30)

=60

position of C from A or B

=(60÷3)×2

=40

possible value of c

=-30+40

=10

possible value of c

=30-40

=-10

8 0
3 years ago
Read 2 more answers
Forgot to do this over winter break. Its due tomorrow and I haven't used my brain for 2 weeks. HELPPP (may have to zoom in)
ANEK [815]
1. 60,30,90 right triangle. y will be hypotenuse/2, x will be
hypotenuse*sqrt(3)/2. So x = 16*sqrt(3)/2 = 8*sqrt(3), approximately 13.85640646 
y = 16/2 = 8  
2. 45,45,90 right triangle (2 legs are equal length and you have a right angle).
X and Y will be the same length and that will be hypotenuse * sqrt(2)/2. So 
x = y = 8*sqrt(2) * sqrt(2)/2 = 8*2/2 = 8 
 3. Just a right triangle with both legs of known length. Use the Pythagorean theorem 
x = sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13  
4. Another right triangle with 1 leg and the hypotenuse known. Pythagorean theorem again. 
y = sqrt(1000^2 - 600^2) = sqrt(1000000 - 360000) = sqrt(640000) = 800  5. A 45,45,90 right triangle. One leg known. The other leg will have the same length as the known leg and the hypotenuse can be discovered with the Pythagorean theorem.  x = 6. y = sqrt(6^2 + 6^2) = sqrt(36+36) = sqrt(72) = sqrt(2 * 36) = 6*sqrt(2), approximately 8.485281374  
6. Another 45,45,90 triangle with the hypotenuse known. Both unknown legs will have the same length. And Pythagorean theorem will be helpful. 
x = y. 
12^2 = x^2 + y^2 
12^2 = x^2 + x^2 
12^2 = 2x^2 
144 = 2x^2 
72 = x^2 
sqrt(72) = x 
6*sqrt(2) = x 
x is approximately 8.485281374  
7. A 30,60,90 right triangle with the short leg known. The hypotenuse will be twice the length of the short leg and the remaining leg can be determined using the Pythagorean theorem. 
y = 11*2 = 22. 
x = sqrt(22^2 - 11^2) = sqrt(484 - 121) = sqrt(363) = sqrt(121 * 3) = 11*sqrt(3). Approximately 19.05255888  
8. A 30,60,90 right triangle with long leg known. Can either have fact that in that triangle, the legs have the ratio of 1:sqrt(3):2, or you can use the Pythagorean theorem. In this case, I'll use the 1:2 ratio between the unknown leg and the hypotenuse along with the Pythagorean theorem. 
x = 2y 
y^2 = x^2 - (22.5*sqrt(3))^2 
y^2 = (2y)^2 - (22.5*sqrt(3))^2 
y^2 = 4y^2 - 1518.75 
-3y^2 = - 1518.75 
y^2 = 506.25 = 2025/4 
y = sqrt(2025/4) = sqrt(2025)/sqrt(4) = 45/2 
Therefore: 
y = 22.5
 x = 2*y = 2*22.5 = 45  
9. Just a generic right triangle with 2 known legs. Use the Pythagorean theorem. 
x = sqrt(16^2 + 30^2) = sqrt(256 + 900) = sqrt(1156) = 34  
10. Another right triangle, another use of the Pythagorean theorem. 
x = sqrt(50^2 - 14^2) = sqrt(2500 - 196) = sqrt(2304) = 48
8 0
3 years ago
Just welp me finish this math stuff pls
kykrilka [37]

Answer:

2/7

Step-by-step explanation:

You would add what is in the parenthesees and you get 6/14 and if you simplify you get 3/7. So you would do 5/7 -3/7

8 0
3 years ago
Read 2 more answers
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