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1 year ago

One equation in a system is y=3x+7. Which equation gives the system no solution

Mathematics

2 answers:

atroni [7]1 year ago

7 0

Answer:

Step-by-step explanation:

Because I know how to do it

AnnyKZ [126]1 year ago

6 0

I just need the money points

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What is the perimeter, P, of a rectangle that has a length of x + 5 and a width of y − 1?

Helen [10]

Answer:P=2x + 2y + 8

Step-by-step explanation: Perimeter (p) =2L+ 2w

P= 2(x+5)+2(y-1)

Remove bracket

P=2x+ 10 +2y - 2

P=2x+2y+8

6 0

3 years ago

Ryan $65 for n books. Write an expression that can be used to find the cost of one book.

eimsori [14]

Answer:

x=65/n where x is 1 book and n the number of books

Step-by-step explanation:

If n is the number of books, lets say 1 book is "x", then

nx=65

x=65/n

for example

n=1 then x=65

n=2 then x=65/2

n=3 then x=65/3

5 0

2 years ago

A man who is 6 ft tall is standing next to a flagpole. The shadow of the man is 3.5 ft and the shadow of the flagpole is 17.5 ft

rjkz [21]

Answer: 30 ft

Step-by-step explanation:

Cross multiply:

6 : 3.5

x : 17.5

Then divide 105 with 3.5x.

105/3.5x = 30

5 0

3 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the gi

sasho [114]

Equation of a line passing through point (x1, y1) with slope m is given by y - y1 = m(x - x1)
For parallel lines, the slope of the required line is equal to the slope of the given line.
x = -3 is a vertical line, therefore, the required line will also be a vertical line since they are parallel.
Since the required line passes through point (4, 2), the equation of the required line is x = 4.

7 0

2 years ago