All categories

2 years ago

One equation in a system is y=3x+7. Which equation gives the system no solution

Mathematics

2 answers:

atroni [7]2 years ago

7 0

Answer:

Step-by-step explanation:

Because I know how to do it

AnnyKZ [126]2 years ago

6 0

I just need the money points

You might be interested in

Solve for x <br> X= 6<br> X=15<br> X=30<br> X=90

Natalija [7]

Answer:

x=30

Step-by-step explanation:

4x+2x=180

6x=180

x=30

4 0

2 years ago

I'm supposed to simplify this.

tekilochka [14]

Answer:

Step-by-step explanation:

the proof of the answer is seen in the diagram

4 0

3 years ago

The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then

$\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v$

$\implies\ln|u|=\ln|v|+C$

$\implies\ln(y^2+4)=\ln|\ln x|+C$

$\implies y^2+4=e^{\ln|\ln x|+C}$

$\implies y^2=C|\ln x|-4$

$\implies y=\pm\sqrt{C|\ln x|-4}$

4 0

3 years ago

Need help!!! I-ready math!!!!!

Alexus [3.1K]

Answer:

It is skewed left because most of the points are to the left

Hope this helps :)

6 0

3 years ago

If f(x)=3x-7, find f(x)=2

Arisa [49]

Answer:

x = 2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers