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2 years ago

One equation in a system is y=3x+7. Which equation gives the system no solution

Mathematics

2 answers:

atroni [7]2 years ago

7 0

Answer:

Step-by-step explanation:

Because I know how to do it

AnnyKZ [126]2 years ago

6 0

I just need the money points

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Write a polynomial in factored form.

enyata [817]

Answer:

f(x)= x^3

Step-by-step explanation:

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2 years ago

Factor 6(2p q)^2 -5(2p q) - 25

kherson [118]

Treat the 2p+q as x

6x2-5x-25
trial and error
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3 0

3 years ago

MAJOR HELP!! Please help someone please..

VMariaS [17]

Answer:

x=8.48

Step-by-step explanation:

Sin 45 = x/12

x=12 x sin 45

x=12 x .7071

x=8.48

7 0

2 years ago

Thomas wants to invite Madeline to a party. He has an 80% chance of bumping into her at school. Otherwise, he'll call her on the

mash [69]

Answer:

The probability of Thomas inviting Madeline to the party over the phone is 0.143.

Step-by-step explanation:

Consider the tree diagram below.

The events are denoted as follows:

A = Thomas bumps into Madeline at school

B = Thomas call Madeline on the phone

X = Thomas asks Madeline to the party

The information provided is:

P (A) = 0.80

P (B) = 1 - P (A) = 1 - 0.80 = 0.20

P (X|A) = 0.90

⇒ P (X'|A) = 1 - P (X|A) = 1 - 0.90 = 0.10

P (X|B) = 0.60

⇒ P (X'|B) = 1 - P (X|B) = 1 - 0.60 = 0.40

The conditional probability of event U given that another events V has already occurred is:

$P(U|V)=\frac{P(V|U)P(U)}{P(V)}$

The law of total probability states that:

$P(V)=P(V|U)P(U)+P(V|U')P(U')$

In this case we need to determine the probability that Thomas invites Madeline to the party over the phone, i.e. P (B|X).

Use the law of total probability to determine the value of P (X) as follows:

$P(X) = P(X|A)P(A)+P(X|B)P(B)$

$=(0.90\times 0.80)+(0.60\times 0.20)\\=0.72+0.12\\=0.84$

Compute the value of P (B|X) as follows:

$P(B|X)=\frac{P(X|B)P(B)}{P(X)}$

$=\farc{0.60\times 0.20}{0.84}\\\\=0.14286\\\\\approx 0.143$

Thus, the probability of Thomas inviting Madeline to the party over the phone is 0.143.

6 0

3 years ago

I rlly need help with this :(

kobusy [5.1K]

Using the normal distribution, it is found that:

a) The pilot is at the 72th percentile.

b) 19.13% of pilots are unable to fly.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 72.6, \sigma = 2.7$ .

Item a:

The percentile is the p-value of Z when X = 74.2, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{74.2 - 72.6}{2.7}$

Z = 0.59

Z = 0.59 has a p-value of 0.7224.

72th percentile.

Item b:

The proportion that is able to fly is the p-value of Z when X = 78 subtracted by the p-value of Z when X = 70, hence:

X = 78:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{78 - 72.6}{2.7}$

Z = 2

Z = 2 has a p-value of 0.9772.

X = 70:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{70 - 72.6}{2.7}$

Z = -0.96

Z = -0.96 has a p-value of 0.1685.

0.9772 - 0.1685 = 0.8087 = 80.87%.

Hence the percentage that is unable to fly is:

100 - 80.87 = 19.13%.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0

2 years ago