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iogann1982 [59]
3 years ago
14

Kyle stood on a bridge and threw a rock up and over the side. The height of the rocks in meters can be approximated by approxima

ted by -5t^2+5t+24, where T is the time in seconds after car through it completely factor the expression
Mathematics
1 answer:
mojhsa [17]3 years ago
8 0

Answer:

The factorized expression is (-5) × (t - 2.747) ×(t - 1.747)

Step-by-step explanation:

The given expression is -5·t² + 5·t + 24

To factorize the expression by completing the square method, we equate the expression to zero to get;

-5·t² + 5·t + 24 = 0

WE divide by -5 to get;

t² - t - 24/5 = 0

t² - t = 24/5

t² - t + 1/4 = 24/5 + 1/4

(t - 1/2)² = 5.05

t - 1/2 = ±√5.05

t = 1/2 + √5.05, 1/2 - √5.05

The factorized expression becomes;

(t - 1/2 + √5.05) and (t - 1/2 - √5.05)

Which gives;

(t - 2.747) ×(t - 1.747)

The factorized expression is (-5) × (t - 2.747) ×(t - 1.747).

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OC and OR are similar. Find the length of QP.
Elena L [17]

Given:

Circle C and circle R are similar.

The length of arc AB is s = \frac{22 \pi}{9}

The radius of circle C (AC) = 4 unit

The radius of circle R (QR) =6 unit

To find the length of arc QP.

Formula

The relation between s,  r and \theta is

arclength = 2\pi r \frac{\theta}{360}

where,

s be the length of the arc

r be the radius

\theta be the angle.

Now,

For circle C

Taking r = 4

According to the problem,

2 \pi r \frac{\theta}{360} = \frac{22 \pi}{9}

or, 2r \frac{\theta}{360} = \frac{22}{9} [ eliminating \theta from both side]

or, \theta = \frac{(22)(360)}{(9)(2)(4)}

or, \theta = 110^\circ

Again,

For circle R

Taking, r = 6 and \theta = 110^\circ we get,

The length of arc QP is

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or, arclength = \frac{11 \pi}{3}

Hence,

The length of QP is \frac{11 \pi}{3}. Option C.

5 0
3 years ago
What is the equation of the function that is graphed as line b?
Juli2301 [7.4K]

Following the slope of the line at x= 0 the line is at y =1 , at x=, it is at Y = 1.5, so the slope is 1/2

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ohaa [14]

Answer:

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Step-by-step explanation:

So, do that!

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