An object has a mass of 10 grams and a volume of 5cm3 what is the density of the object?

Calculate the volume of 0.684mol of carbon dioxide at s.t.p. show working

solong [7]

Answer: The volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 0.684

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $273K$ (at STP)

$V=\frac{nRT}{P}$

$V=\frac{0.684\times 0.0821L atm/K mol\times 273K}{1atm}$

$V=15.3L$

Thus the volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

6 0

3 years ago

Hydrogen bromide decomposes when heated to 437C according to the equation: 2HBr(g) H2(g) Br2(g). If the reaction starts with 2.1

iren [92.7K]

Answer:

<h3>the equilibrium constant of the decomposition of hydrogen bromide is 0.084</h3>

Explanation:

Amount of HBr dissociated

$2.15 \ mole \times \frac{36.7}{100} \\\\=0.789 \ mole$

2HBr(g) ⇆ H2(g) + Br2(g)

Initial Changes 2.15 0 0 (mol)

- 0.789 + 0.395 + 0.395 (mol)

At equilibrium 1.361 0.395 0.395 (mole)

Concentration 1.361 / 1 0.395 / 1 0.395 / 1

at equilibrium (mole/L)

$K_c=\frac{[H_2][Br_2]}{[HBr]^2} \\\\=\frac{(0.395)(0.395)}{(1.361)^2} \\\\=\frac{0.156025}{1.852321} \\\\=0.084$

<h3>Therefore, the equilibrium constant of the decomposition of hydrogen bromide is 0.084</h3>

6 0

3 years ago

How many moles of oxygen gas molecules would you need to make 12.5 moles of water

horrorfan [7]

Answer: 6.25 mol

Explanation:

From the reaction that produces water from its elements (shown in the image), we know that for every mole of oxygen gas consumed, 2 moles of water are produced.

This means that 12.5/2=<u>6.25 mol</u> of oxygen gas is needed.

7 0

2 years ago

A reaction between liquid reactants takes place at −10.0°C in a sealed, evacuated vessel with a measured volume of 45.0L. Measur

maks197457 [2]

Answer: 0.0624 atm

Explanation:-

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = ?

V= Volume of the gas = 45.0 L

T= Temperature of the gas = -10.0°C = 263 K $0^00C=273K$

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas

Moles of gas= $\frac{\text{ given mass}}{\text{ molar mass}}= \frac{19.0g}{146g/mole}=0.130moles$

$P=\frac{nRT}{V}=\frac{0.130\times 0.0821\times 263}{45.0}=0.0624atm$

The pressure of sulfur hexafluoride gas in the reaction vessel after the reaction is 0.0624 atm

3 0

3 years ago

A certain chemical reaction releases 36.2 kJ/g of heat for each gram of reactant consumed. How can you calculate what mass of re

Lilit [14]

Answer:

0.038 g of reactant

Explanation:

Data given:

Heat release for each gram of reactant consumption = 36.2 kJ/g

mass of reactant that release 1360 J of heat = ?

Solution:

As 36.2 kJ of heat release per gram of reactant consumption so first we will convert KJ to J

As we know

1 KJ = 1000 J

So

36.2 kJ = 36.2 x 1000 = 36200 J

So it means that in chemical reaction 36200 J of heat release for each gram of reactant consumed so how much mass of reactant will be consumed if 1360 J heat will release

Apply unity formula

36200 J of heat release ≅ 1 gram of reactant

1360 J of heat release ≅ X gram of reactant

Do cross multiplication

X gram of reactant = 1 g x 1360 J / 36200 J

X gram of reactant = 0.038 g

So 0.038 g of reactant will produce 1360 J of heat.

5 0

3 years ago