Sub x = 2-y^2 to Q, we get:
Q = 3(2-y^2)*y^2
let y^2 = k
Q = 3(2-k)k = 3(2k-k^2)
2k-k^2 has a max when k = 1
Then y^2 = 1 -> y = 1 or -1
It depends on what level of classes you take, but algebra classes in college do tend to be harder than algebra classes in high school or middle school.
Answer:
Step-by-step explanation:
Here's the thing. It is easier to figure out the probability of not getting a six even once during the 50 rolls.
The chance of that happening is (5/6)^50 = 0.00010988
So the probability is succeeding is (1 - 0.00010988) = 0.9999 rounded to 4 places.
$125 billion in scientific notation is 1.25*1011
I would say Ben because the chance of the numbers being 1,2,3,4,5, 6 would be extremely low
