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3 years ago

A gas that exists in outer space is made of

Physics

2 answers:

vlabodo [156]3 years ago

7 0

Do you mean on a planet?

Deffense [45]3 years ago

7 0

<span>Helium and hydrogen found in the sun make up most of the ISM. Hydrogen clouds in the ISM can cool, collapse under the force of gravitation and eventually form new stars. If this gas did not exist, no new stars could form. The M33 galaxy is a classic example of a massive stellar nursery. About 3 million years ago, a giant gas cloud in this galaxy began collapsing and forming stars that the Hubble telescope can see.</span>

You might be interested in

What kind of quantity is displacement?

Serhud [2]

Answer:

calar quantity, length of path. displacement: vector quanity, "as the crow flies" difference between start and finish regardless of path taken. Term.

Explanation:

8 0

3 years ago

When the lights of an automobile are switched on, an ammeter in series with them reads 12 A and a voltmeter connected across the

Anarel [89]

Answer:

a) Emf of battery = 15.6 V

b) Current through the starting motor = 104 A

Explanation:

The image for the question seem not to be attached but, when the starting motor wasn't connected, the lights are in series with the battery connection and when the starting motor is connected, it is in parallel with the lights.

a) For this part, we use the information when the starting motor isn't connected.

Let the emf of the battery be E = ?

The voltage across the terminals be V = 15 V

Let the internal resistance of the battery be R = 0.05 ohms

And the current in the circuit be I = 12 A

Since the internal resistance is modelled to be in series with the battery, the loop equation for this circuit will be

E = V + IR

E = 15 + (12)(0.05) = 15 + 0.6 = 15.6 V

From this information now, we can obtain the resistance of the lights.

From Ohm's law,

Voltage across the lights = 15 V

Current through the lights = 12 A

Resistance of the lights = R₀

V = IR₀

R₀ = (15/12) = 1.25 ohms

b) Now, the starting motor is connected and the resistance in the circuit is if the form

Internal resistance in series with the parallel combination of resistance of starting motor and the resistance of the lights.

Current through the lights = 8.0 A

Voltage across the lights = IR₀ = 8×1.25 = 10 V.

Since the starting motor is in parallel with the lights, they will have the same voltage across them, that is, 10 V

But the voltage across the internal resistance = (Emf of battery) - (Voltage across the parallel combination of lights and starting motor) = 15.6 - 10 = 5.6 V

Current through the internal resistance = (5.6/0.05) = 112 A

Current through the starting motor = 112 - 8 = 104 A

Hope this Helps!!!

3 0

4 years ago

Read 2 more answers

a balloon rubbed against denim gains a charge of -8.0 x 10^-6 c. What is the electric force between the balloon and the denim, w

DedPeter [7]

Answer:

230.4 N

Explanation:

Applying,

F = kqq'/r²..................... Equation 1

Where F = Electric force, k = Coulomb's constant, q = charge in the ballon, q' = charge in the denium, r = distance between the charges.

From the question,

Given: q = -8.0×10⁻⁶ C, q' = +8.0×10⁻⁶ C, r = 0.05 m

Constant: k = 9×10⁹ Nm²/C²

Substitute these values into equation 1

F = (9×10⁹×8.0×10⁻⁶×8.0×10⁻⁶ )/0.05²

F = (576×10⁻³)/0.0025

F = 230.4 N.

6 0

3 years ago

In order for water to condense on an object, the temperature of the object must be ______ the dewpoint temperature.

enyata [817]

Answer:

at ( or below)

Explanation:

at the dewpoint.......water will condense out of the air onto the surface

7 0

2 years ago

A heavy flywheel is accelerated (rotationally) by a motor that provides constant torque and therefore a constant angular acceler

ki77a [65]

Answer:

a) $t_1=\frac{w_1-w_o}{\alpha}=\frac{w_1}{\alpha}sec$

b) $\theta_1=\frac{w_1^2}{2\alpha}rad$

c) $t_2=\frac{\alpha t_1}{5\alpha}=\frac{t_1}{5}sec$

Explanation:

1) Basic concepts

Angular displacement is defined as the angle changed by an object. The units are rad/s.

Angular velocity is defined as the rate of change of angular displacement respect to the change of time, given by this formula:

$w=\frac{\Delat \theta}{\Delta t}$

Angular acceleration is the rate of change of the angular velocity respect to the time

$\alpha=\frac{dw}{dt}$

2) Part a

We can define some notation

$w_o=0\frac{rad}{s}$ ,represent the initial angular velocity of the wheel

$w_1=?\frac{rad}{s}$ , represent the final angular velocity of the wheel

$\alpha$ , represent the angular acceleration of the flywheel

$t_1$ time taken in order to reach the final angular velocity

So we can apply this formula from kinematics:

$w_1=w_o +\alpha t_1$

And solving for t1 we got:

$t_1=\frac{w_1-w_o}{\alpha}=\frac{w_1}{\alpha}sec$

3) Part b

We can use other formula from kinematics in order to find the angular displacement, on this case the following:

$\Delta \theta=wt+\frac{1}{2}\alpha t^2$

Replacing the values for our case we got:

$\Delta \theta=w_o t+\frac{1}{2}\alpha t_1^2$

And we can replace $t_1$ from the result for part a, like this:

$\theta_1-\theta_o=w_o t+\frac{1}{2}\alpha (\frac{w_1}{\alpha})^2$

Since $\theta_o=0$ and $w_o=0$ then we have:

$\theta_1=\frac{1}{2}\alpha \frac{w_1^2}{\alpha^2}$

And simplifying:

$\theta_1=\frac{w_1^2}{2\alpha}rad$

4) Part c

For this case we can assume that the angular acceleration in order to stop applied on the wheel is $\alpha_1 =-5\alpha \frac{rad}{s}$

We have an initial angular velocity $w_1$ , and since at the end stops we have that $w_2 =0$

Assuming that $t_2$ represent the time in order to stop the wheel, we cna use the following formula

$w_2 =w_1 +\alpha_1 t_2$

Since $w_2=0$ if we solve for $t_2$ we got

$t_2=\frac{0-w_1}{\alpha_1}=\frac{-w_1}{-5\alpha}$

And from part a) we can see that $w_1=\alpha t_1$ , and replacing into the last equation we got:

$t_2=\frac{\alpha t_1}{5\alpha}=\frac{t_1}{5}sec$

5 0

3 years ago