Cathode ray tube, plumb pudding model, atoms were not hard spheres, but had smaller parts.
A fluorescent light bulb is the most energy efficient in this group.
The resistance of a wire is given by

where

is the resistivity of the material, L the length of the wire and A its cross-sectional area.
In the problem,

and L remain the same, while A changes because the radius changes. The area is given by:

This means that if we double the radius (2r), the area becomes

And therefore, the new value of the resistance is

So, when the radius is doubled, the resistance becomes

of its original value.
If 56.5kJ are needed to raise the temp by 90°C and if the heater is 60% efficient that means that:
60% X y = 56.5kJ
where y is the electrical energy in kJ that the heater will use.
y = 94.2kJ
An "Electric Circuit" <span>is any path through which electrons can flow.
Hope this helps!</span>