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FinnZ [79.3K]
3 years ago
10

In which parking situations should you use your parking brake?

Physics
2 answers:
vredina [299]3 years ago
6 0

Answer:

Always!!

Explanation:

I hope it help! :D

VMariaS [17]3 years ago
5 0
Answer:
-You should use your parking brake when on a hill/mountain with a huge drop because your car can’t slide off the edge.
-When there is a flood where your car is sitting because the water can’t carry your car
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View this and help out??
Zina [86]
I would say b as well. I’m sorry if it’s wrong
5 0
3 years ago
(5, 3) and (7, 3) are two coordinate points for a single object on a position-versus-time graph. Assume time is measured in seco
Maru [420]
Since the y axis stayed consistent, we can assume it did not move at all.
(So your answer would be A)
6 0
3 years ago
Read 2 more answers
What are two things that are infinite?
yaroslaw [1]

Answer:

Infinity = Never ending

Explanation:

The universe could be infinite, both in terms of space and time, but there is currently no way to test whether it goes on forever or is just very big. The part of the universe we are able to observe is finite, measuring about 46 billion light years in diameter.

The set of natural numbers is an infinite set. This kind of infinity is, by definition, called countable infinity. All sets that can be put into a bijective relation to the natural numbers are said to have this kind of infinity. This is also expressed by saying that the cardinal number of the set is aleph-naught (ℵ0).

Hope this helps. Mark as brainliest!

6 0
3 years ago
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Monochromatic light falls on two very narrow slits 0.048 mm apart. successive fringes on a screen 5.00 m away are 6.5 cm apart n
atroni [7]
In a double-slit interference experiment, the distance y of the maximum of order m from the center of the observed interference pattern on the screen is
y= \frac{m \lambda D}{d}
where D=5.00 m is the distance of the screen from the slits, and 
d=0.048 mm=0.048 \cdot 10^{-3}m is the distance between the two slits.
The fringes on the screen are 6.5 cm=0.065 m apart from each other, this means that the first maximum (m=1) is located at y=0.065 m from the center of the pattern.
Therefore, from the previous formula we can find the wavelength of the light:
\lambda =  \frac{yd}{mD}= \frac{(0.065 m)(0.048 \cdot 10^{-3}m)}{(1)(5.00 m)}=  6.24 \cdot 10^{-7}m

And from the relationship between frequency and wavelength, c=\lambda f, we can find the frequency of the light:
f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{6.24 \cdot 10^{-7}m}=4.81 \cdot 10^{14}Hz
4 0
3 years ago
Which statement is correct
daser333 [38]

C Weight is the gravitational pull on an object

8 0
3 years ago
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