Answer:
The ball will take 4.05 seconds to hit the ground.
Step-by-step explanation:
we have
![h=-16t^{2}+64t+3](https://tex.z-dn.net/?f=h%3D-16t%5E%7B2%7D%2B64t%2B3)
This is a quadratic equation (vertical parabola) open down
The vertex is a maximum
we know that
The ball hit the ground when h=0
Solve the quadratic equation
For h=0
![-16t^{2}+64t+3=0](https://tex.z-dn.net/?f=-16t%5E%7B2%7D%2B64t%2B3%3D0)
The formula to solve a quadratic equation of the form
is equal to
![t=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-b%28%2B%2F-%29%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%7D%20%7B2a%7D)
in this problem we have
so
![a=-16\\b=64\\c=3](https://tex.z-dn.net/?f=a%3D-16%5C%5Cb%3D64%5C%5Cc%3D3)
substitute in the formula
![t=\frac{-64(+/-)\sqrt{64^{2}-4(-16)(3)}} {2(-16)}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-64%28%2B%2F-%29%5Csqrt%7B64%5E%7B2%7D-4%28-16%29%283%29%7D%7D%20%7B2%28-16%29%7D)
![t=\frac{-64(+/-)\sqrt{4,288}} {-32}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-64%28%2B%2F-%29%5Csqrt%7B4%2C288%7D%7D%20%7B-32%7D)
---> the time cannot be a negative number
![t=\frac{64(+)\sqrt{4,288}} {32}=4.05\ sec](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B64%28%2B%29%5Csqrt%7B4%2C288%7D%7D%20%7B32%7D%3D4.05%5C%20sec)
therefore
The ball will take 4.05 seconds to hit the ground.
Answer:
Graph B
Step-by-step explanation:
The answer is b .........
Answer:
b - 9 = 2 I believe would be it
Answer:
The answer is (0, 2)
Step-by-step explanation:
Ive also had this question and viewed iver it and said it was right this was some time ago but im glad to help :)