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Lina20 [59]
2 years ago
14

30 points Select the expression that has a sum of seventy four hundredths.

Mathematics
1 answer:
qwelly [4]2 years ago
4 0

Answer:

A, If you still need help

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A city planner is rerouting traffic in order to work on a stretch of road. The equation of the path of the old route can be desc
g100num [7]

Answer:

y - Q = -5/2(x - P)

Step-by-step explanation:

The equation of a line in point slope form is expressed as y - y0 = m(x-x0)

(x0, y0) is the point

m is the slope

Given the equation

y = 2/5x− 4.

Slope m  = 2/5

Slope of the perpendicular line = -1/(2/5) = -5/2

Point;

x0 = P

y0 = Q

Substitute into the formula;

y - y0 = m(x-x0)

y - Q = -5/2(x - P)

This gives the required equation

5 0
2 years ago
A fair, twenty-faced die has $19$ of its faces numbered from $1$ through $19$ and has one blank face. another fair, twenty-faced
lawyer [7]
Represent 24 as a sum of two numbers, first number from first die and second number from second die.
24=19+5=18+6=17+7=16+8=14+10=13+11=12+12=11+13=10+14=9+15=8+16=7+17=6+18=5+19=4+20 (the sums 15+9 and 20+4 are absent, because there aren't numbers: 20 on the first die and number 9 on the second die). Totally, you receive 15 different representations of 24.
<span>The probability that the sum of the two numbers facing up will be 24 is
</span><span>
</span><span>P= \frac{15}{20\cdot 20} = \frac{3}{80} (here 20\cdot 20 means that you have 20 possibilities to roll first number or blank face on the first die and 20 possibilities to roll number or blank face on the second die).
</span>


8 0
3 years ago
11. Write 850 as the product of its prime factors. A. 17 × 50 B. 5 × 10 × 17 C. 10 × 85 D. 2 × 5 × 5 × 17
RideAnS [48]
D. 2 x 5 x 5 x 17 

hope this helps
4 0
3 years ago
Randy and Sandy have a total of 20 books between them. After Sandy loses three by leaving them on the bus, and some birthday gif
nasty-shy [4]

Answer:

Randy had 13 books an Sandy had 7 books.

Step-by-step explanation:

20 - 3 = 17

30 - 17 = 13

13 x 2 = 26

26 + 4 = 30

13 + 7 = 20

Hope this helps! Please mark as brainliest.

3 0
3 years ago
VEEL
Andre45 [30]

Answer:

a_n=-3(3)^{n-1} ; {-3,-9, -27,- 81, -243, ...}

a_n=-3(-3)^{n-1} ; {-3, 9,-27, 81, -243, ...}

a_n=3(\frac{1}{2})^{n-1} ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

a_n=243(\frac{1}{3})^{n-1} ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

a_n=-3(3)^{n-1}

At n=1,

a_1=-3(3)^{1-1}=-3

At n=2,

a_2=-3(3)^{2-1}=-9

At n=3,

a_3=-3(3)^{3-1}=-27

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

a_n=-3(-3)^{n-1}

At n=1,

a_1=-3(-3)^{1-1}=-3

At n=2,

a_2=-3(-3)^{2-1}=9

At n=3,

a_3=-3(-3)^{3-1}=-27

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

a_n=3(\frac{1}{2})^{n-1}

At n=1,

a_1=3(\frac{1}{2})^{1-1}=3

At n=2,

a_2=3(\frac{1}{2})^{2-1}=1.5

At n=3,

a_3=3(\frac{1}{2})^{3-1}=0.75

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

a_n=243(\frac{1}{3})^{n-1}

At n=1,

a_1=243(\frac{1}{3})^{1-1}=243

At n=2,

a_2=243(\frac{1}{3})^{2-1}=81

At n=3,

a_3=243(\frac{1}{3})^{3-1}=27

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0
3 years ago
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