Answer:
you subtract 14 from -9 and that justifies it
Step-by-step explanation:
Hope this helps
Answer:
0.1333 = 13.33% probability that bridge B was used.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Arrives home by 6 pm
Event B: Bridge B used.
Probability of arriving home by 6 pm:
75% of 1/3(Bridge A)
60% of 1/6(Bridge B)
80% of 1/2(Bridge C)
So

Probability of arriving home by 6 pm using Bridge B:
60% of 1/6. So

Find the probability that bridge B was used.

0.1333 = 13.33% probability that bridge B was used.
Answer:
Step-by-step explanation:
Without a second equation relating x and y, we can solve 3x - 1/2y = 2 ONLY for x in terms of y or for y in terms of x:
x in terms of y: Multiply all three terms of 3x - 1/2y = 2 by 2, to eliminate the fraction: 6x - y = 4. Now add y to both sides to isolate 6x: 6x = 4 + y.
Last, divide both sides by 6 to isolate x:
x = (4 + y)/6
y in terms of x:
y = 6x - 4
If you want a numerical solution, please provide another equation in x and y and solve the resulting system.
Mmm... I think it is 5/8... I think.