Answer:
(130.08, 139.92)
Step-by-step explanation:
Given that:
Mean (m) = 135
Standard deviation (σ) = 30
Sample size (n) = 100
α = 90%
The confidence interval value is obtained using the relation:
Mean ± Zcritical * (standard deviation / sqrt(n))
Zcritical at 90% = 1.64
standard deviation / sqrt(n) = 30 / sqrt(100)
= 30 / 10 = 3
Hence,
135 ± 1.64 * (3)
Lower limit : 135 - (1.64 * 3) = 130.08
Upper limit : 135 + (1.64 * 3) = 139.92
Hence,
Confidence interval = (130.08, 139.92)
Answer
The distance is 13.4164078649987
1. (t-5)^2+3=t^2-10t+12+3=t^2-10t+15.
2. (a+h)^2+3=a^2+2ah+h^2+3
(a^2)+3=a^2+3. Subtracting, we get h^2+2ah.
3. (a^2)+3=a^2+3
(a-h)^2+3=a^2-2ah+h^2+3. Subtracting, we get 2ah-h^2.
Answer:
10
Step-by-step explanation:
just try to make the lines even and get the answer 10