Question

What is the slope of the line that passes through the points (-8, -6) and (-8,4)?

Answer 1

$\small\bold\red{Reminder}{\boxed{{m= \frac{y2- y1}{x2 - x1}}}}$

where m represents the slope and $(x1, y1), (x2, y2)$ 2 points on the line

The 2 points here are (-8,6) and (-8,4)

let ,

$(x1, y1) = (-8,6) and (x2, y2)$

$= (-8, 4)$

$⇒m = \frac{4-6}{-8 - (-8)} = \frac{- 2}{0}$

Division by zero makes m undefined, hence slope is undefined.

Another way is to note that the x-coordinates of the 2 points are equal, that is both - 8

This indicates that the line is vertical and parallel to the y-axis, passing through all points in the plane with an x-coordinate of- 8.

The equation of the line is x = - 8 and since it is vertical has an undefined slope.

The equation of the line is x = - 8 and since it is vertical has an undefined slope.graph{y-1000x-8000=0 [-10, 10, -5, 5]}

Answer 2

• (-8,-6)
• (-8,4)

$\\ \rm\rightarrowtail m=\dfrac{4+6}{-8+8}$

$\\ \rm\rightarrowtail m=10/0$

• Parallel to x axis

$\\ \rm\rightarrowtail m=\infty$