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choli [55]
2 years ago
6

fill in empty circle with +, -, = to create equatioins that are true from top to bottom and left to right

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
4 0

Answer:

You forgot to include the equations

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Plz help 13 brainly for correct anwser and brainleyist.
aliina [53]

Answer:

height of the warriors and Panthers vary the same amount

Step-by-step explanation:

this is because the height are closer to each other in number.

4 0
3 years ago
(b) At noon on Saturday, the temperature was 15 °C.
Thepotemich [5.8K]
Their is a 18 degree difference
5 0
3 years ago
Please tell me this asap..<br><br>y/2 - 1/5 = 2 - y/3​
musickatia [10]

Answer:

y=2 16/25

in other words, two and sixteen twenty-fifths

Step-by-step explanation:

y/2-1/5=2-y/3

Move the variables to one side and constants to the other

y/2+y/3=2+1/5

Multiply y/2 by 3/3 and y/3 by 2/2 so that they have a common denominator

3y/6+2y/6=2 1/5

5y/6=11/5

Cross multiply

66=25y

y=66/25

y=2 16/25

HOPE THIS HELPS!!!

8 0
3 years ago
Find the area of the shaded region in each of the following.​
zysi [14]

Answer:

Step-by-step explanation:

a) A = ½(5 - -1)(5) = 15 units²

b) A = ½(4 - 2)(4) = 4 units²

c) A = ½(6 - -3)(3) = 13.5 units²

d) A = ½(4 - -1)(8) = 20 units²

5 0
3 years ago
Among all monthly bills from a certain credit card company, the mean amount billed was $465 and the standard deviation was $300.
Fynjy0 [20]

Answer:

0.02% probability that the average amount billed on the sample bills is greater than $500.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 465, \sigma = 300, n = 900, s = \frac{300}{\sqrt{900}} = 10.

What is the probability that the average amount billed on the sample bills is greater than $500?

This probability is 1 subtracted by the pvalue of Z when X = 500. So

Z = \frac{X - \mu}{s}

Z = \frac{500 - 465}{10}

Z = 3.5

Z = 3.5 has a pvalue of 0.9998.

So there is a 1-0.9998 = 0.0002 = 0.02% probability that the average amount billed on the sample bills is greater than $500.

8 0
3 years ago
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