Answer:
AC= 6.3 units (nearest tenth)
BC= 2.8 units (nearest tenth)
∠C= 64°
Step-by-step explanation:
Please see attached picture for full solution.
A rhombus area is height times base because has 2 parralell sides and the area of a paralellogram is found by multiplying height by base (aka width)
even though this might not seem wrong, it is correct
so area=height times base
see attachment below
Answer:
Aaron=110
Betty=210
Step-by-step explanation:
the photo contains the needed working out
Answer:
f < 0
Step-by-step explanation:
33 + 6f < 33 ( subtract 33 from both sides )
6f < 0 ( divide both sides by 6 )
f < , that is
f < 0
The probability that a student chosen at random has a cat and a dog is
Step-by-step explanation:
The addition rules of probability are:
- P(A or B) = P(A) + P(B) ⇒ mutually exclusive (events cannot happen at the same time)
- P(A or B) = P(A) + P(B) - P(A and B) ⇒ non-mutually exclusive (if they have at least one outcome in common)
The rule of probability is P(A) =
∵ A class has 25 students
∵ 15 of them have a cat
∴ n(cat) = 15
- By using the rule of probability
∴ P(cat) =
∵ 16 of them have a dog
∴ n(dog) = 16
- By using the rule of probability
∴ P(dog) =
∵ 3 of them have neither
- Subtract from the total of the class to find the number of
students that have a cat or a dog
∴ n(cat or dog) = 25 - 3
∴ n(cat or dog) = 22
- By using the rule of probability
∴ P(cat or dog) =
To find the probability that a student has a cat and a dog use the non-mutually rule of addition above
∵ P(cat or dog) = P(cat) + P(dog) - P(cat and dog)
∴ = + - P(cat and dog)
- Add the like terms in the right hand side
∴ = - P(cat and dog)
- Subtract from both sides
∴ = - P(cat and dog)
- Multiply both sides by -1
∴ = P(cat and dog)
- Switch the two sides
∴ P(cat and dog) =
The probability that a student chosen at random has a cat and a dog is
Learn more:
You can learn more about probability in brainly.com/question/9178881
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