Seca(1-sina)(seca+tana)=1
Left hand side
=(1-sina) (seca +tana) / cosa
=seca +tana - sinaseca - sinatan / cosa
=seca + tana -tana -(sin^2a/cosa) / cosa
=(1/cosa - sin^2a/cosa) / cosa
= (1-sin^2a / cosa) / cosa
= (1-sin^2a)/ (cos^2a)
=1 (verified)
Answer:
this equation id 2=0 meaning no solution
Step-by-step explanation:
Sum of complementary angles always equal to 90°.
Given, <A and <J are complementary angles. So, we can set up an equation as following:
m<A+ M<J= 90
Next step is to plug in m<A = 5x + 30 and m<J = 4x +15 in the above equation. So we will get,
5x+30+4x+15=90
(5x+4x)+(30+15)=90 Group the like terms.
9x+45=90 Combine the like terms.
9x+45-45=90-45 Subtract 45 from each sides.
9x=45 By simplifying.
Divide each sides by 9.
x=5.
So, x=5.
Remark
If the lines are parallel, there are no solutions to the system of equations. Start with the equation you know the most about.
x + 6y = 7 Subtract x from both sides
x - x + 6y = 7 - x Combine
6y = - x + 7 Switch and divide by 6
y = -x / 6 + 7/6
The general equation for a line is y = mx + b where m is the slope of the line.
m = - 1/6
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Now look at the second equation
10ay - 5x = 32 Add 5x to both sides
10ay = 5x + 32 Divide by 10a
y = (5/10a)x + 32/(10a)
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Now you must make
5/10a = - 1/6 Cross Multiply
5* 6 = - 10a * 1
30 = - 10a Divide by - 10
a = 30 / - 10
a = - 3
So these two equations will have no solution when a = - 3
√(4x⁵y²/9x³)=√(2²x⁴xy²/3²x²x)=(2x²y√x) / (3x√x)= 2xy/3
Answer: <span>√(4x⁵y²/9x³)=2xy/3</span>
