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Serhud [2]
2 years ago
6

Put the following equation of a line into slope-intercept form, simplifying all fractions. 2x-3y=−9

Mathematics
1 answer:
Paha777 [63]2 years ago
7 0

Answer:

Step-by-step explanation:

Slope-intercept from: y = mx +c

Here, m is the slope & c is the y-intercept.

So, we have to isolate y. To isolate y first subtract 2x from both sides.

2x - 3y = -9

     -3y = -2x -9

Now, divide the entire equation by the co efficient of y (-3)

\dfrac{-3}{-3}y=\dfrac{-2}{-3}x-\dfrac{9}{-3}\\\\\\y=\dfrac{2}{3}x + 3

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4 0
3 years ago
A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

7 0
3 years ago
PLZ QUICK!!
iragen [17]

Answer:

See attached graph

Step-by-step explanation:

The equation is y-3=(x + 6)

Write the equation in a slope intercept form, then graph the equation on a graph tool to see the points that line on the line.

Alternatively , using the coordinates in the answer choices given, input them in the equation of the graph and select the answer choice that has all its coordinates true to the equation.

y-3 = x+6  -----can be written as : y= x+9

Graph  y= x+9 to see the graph and the points that are on the line as attached.

3 0
3 years ago
Read 2 more answers
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