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Vsevolod [243]
2 years ago
13

What is the GCF of the numerator and denominator in the following fraction?

Mathematics
1 answer:
jeyben [28]2 years ago
7 0

Answer:

What's the fraction

Step-by-step explanation:

I need to know the fraction in order to solve

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Write the slope-intercept form of the equation of the line given the
svetoff [14.1K]

Answer:

y= -4x-7 or 4x+y= -7

Step-by-step explanation:

we know y=mx+c

given,

m=-4 c=-7

the equation y= -4x-7 or 4x+y= -7

thank u

5 0
3 years ago
At noon, ship A is 170 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 20 km/h. How fast is
garik1379 [7]
Check the picture below.

now, keep in mind that ship B is going at 20kph, thus from noon to 4pm, is 4 hours, so it has travelled by then 20 * 4 or 80 kilometers, thus b = 80.

whilst the ship B is moving north, the distance "a" is not really changing, and thus is a constant, that matters because the derivative of a constant is 0.

\bf c^2=a^2+b^2\implies \stackrel{chain~rule}{2c\cfrac{dc}{dt}}=0+2b\cfrac{db}{dt}\implies \cfrac{dc}{dt}=\cfrac{b\frac{db}{dt}}{c}
\\\\\\
\begin{cases}
\frac{db}{dt}=20\\
c=10\sqrt{353}\\
b=80
\end{cases}\implies \cfrac{dc}{dt}=\cfrac{80\cdot 20}{10\sqrt{353}}\implies \cfrac{dc}{dt}=\cfrac{160}{\sqrt{353}}
\\\\\\
\textit{and rationalizing the denominator}\implies \cfrac{160\sqrt{353}}{353}

8 0
3 years ago
The equation y = mx + b is in ___-____ form. (2 words)
poizon [28]
<span>The equation y = mx + b is in Slope - intercept form.</span>
5 0
3 years ago
Read 2 more answers
Someone please help, i don't have a lot of time
topjm [15]
<span>Pythagorean triple
a^2 + b^2 = c^2
so
5^2 + 12^2 = 13^2
25 + 144 = 169
169 = 169

answer is D. last one 5, 12 , 13</span>
4 0
3 years ago
What is tan11pi/6 ? Fraction
tamaranim1 [39]
11pi/6 is in 4th quadrant.

The reference angle is pi/6 because 11pi/6 is pi/6 radians away from 'x' axis.

In 4th quadrant, sin is negative and cos is positive, therefore tan is negative.

This means:
tan(\frac{11\pi}{6}) = -tan(\frac{\pi}{6}) = -\frac{sin(\pi/6)}{cos(\pi/6)} = -\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}} = -\frac{1}{\sqrt{3}} = -\frac{\sqrt{3}}{3}
6 0
3 years ago
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