The situation is represented by a right triangle with 2.1km as the hypotenuse. The distance x from the center to the landing point divided by 2.1 is the cosine of 37 degrees. So x/2.1=cos37=0.7986 approx, x=2.1×0.7986=1.68 km.

take the derivitive to find the slope


so at x=1, the slope is f'(1)=6(1)^2-4=6-4=2
y=mx+b
y=2x+b
find b
at x=1, f(1)=2(1)^3-4(1)=2-4=-2=y
-2=2(1)+b
-2=2+b
-4=b
equation is y=2x-4
4k+5+ 6k + 10 = 115
10k + 15 = 115
10k = 100
K = 10°