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yanalaym [24]
2 years ago
12

Why did you test the reaction mixture with starch/iodide paper before starting the separatory funnel steps

Chemistry
1 answer:
-Dominant- [34]2 years ago
3 0

Answer:

This paper is impregnated with iodide ions and starch and will turn black if treated with an oxidizing agent (e.g. HOCl) which oxidizes the iodide ions

Explanation: hope this helps :)

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Electrons in Bohr's model of the atom are at the lowest possible energy state when they are
arlik [135]

Answer:

d. at ground state

Explanation:

Electrons in the Bohr's model of the atom are at the lowest possible energy state when they are their ground state.

The lowest energy state available to an electron is the ground state.

  • According to the the Bohr's model of the atom, the extranuclear part is made up of electrons in specific spherical orbits around the nucleus.
  • In the excited state, the level is higher than the ground state.
  • When electrons changes state they either absorb or gain energy.
8 0
3 years ago
Read 2 more answers
Calculate the temperature change that occurs when 254 cal of heat are added to 24 g of water
Tomtit [17]
Hey

Calculate the temperature change that occurs when 254 cal of heat are added to 24 g of water
answer:  800
3 0
3 years ago
For the reaction 2 HCl + Ca ( OH ) 2 ⟶ CaCl 2 + 2 H 2 O how many grams of calcium hydroxide, Ca(OH)2, are needed to react comple
kari74 [83]

Answer: 65.38g of Ca(OH)2 is needed

Explanation:

From The equation of reaction

2 HCl + Ca ( OH ) 2 ⟶ CaCl 2 + 2 H 2 O

NB: Molar mass of HCl= 1+35.5=36.5

Ca(OH)2= 74

From The stoichiometric equation

2mol of HCl(36.5×2=73) require 1mol of Ca(OH)2 (74g)

Hence 64.5g of HCl will require 64.5×74/73= 65.38g of Ca(OH)2

5 0
3 years ago
How do scientists use sonar to study Earth’s oceans?
adoni [48]
A to map the ocean floor
7 0
3 years ago
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If 23.6 g of hydrogen gas reacts with 28.3 g of nitrogen gas, what is the maximum amount of product that can be produced?
Aleonysh [2.5K]

Answer:

34.3 g NH3

Explanation:

M(H2) = 2*1 = 2 g/mol

M(N2) = 2*14 = 28 g/mol

M(NH3) = 14 + 3*1 = 17 g/mol

23.6 g H2* 1 mol/2 g = 11.8 mol H2

28.3 g N2 * 1 mol/28 g = 1.01 mol N2

                                 3H2 + N2 ------> 2NH3

from reaction         3 mol    1 mol

given                   11.8 mol    1.01 mol

We can see that H2 is given in excess, N2 is limiting reactant.

                                 3H2 + N2 ------> 2NH3

from reaction                     1 mol         2 mol

given                                 1.01 mol      x

x = 2*1.01/1= 2.02 mol NH3

2.02 mol * 17g/1 mol ≈ 34.3 g NH3

8 0
3 years ago
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