Why did you test the reaction mixture with starch/iodide paper before starting the separatory funnel steps

Chemistry

1 answer:

-Dominant- [34]1 year ago

3 0

Answer:

This paper is impregnated with iodide ions and starch and will turn black if treated with an oxidizing agent (e.g. HOCl) which oxidizes the iodide ions

Explanation: hope this helps :)

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Soil that are light in color have a great amount of humus in<br> them. True or False

GaryK [48]

Answer:

please the answer Is false

6 0

2 years ago

When the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is

gizmo_the_mogwai [7]

Answer : The correct option is, (D) 100 times the original content.

Explanation :

As we are given the pH of the solution change. Now we have to calculate the ratio of the hydronium ion concentration at pH = 5 and pH = 3

As we know that,

$pH=-\log [H_3O^+]$

The hydronium ion concentration at pH = 5.

$5=-\log [H_3O^+]$

$[H_3O^+]=1\times 10^{-5}M$ ..............(1)

The hydronium ion concentration at pH = 3.

$3=-\log [H_3O^+]$

$[H_3O^+]=1\times 10^{-3}M$ ................(2)

By dividing the equation 1 and 2 we get the ratio of the hydronium ion concentration.

$\frac{[H_3O^+]_{original}}{[H_3O^+]_{final}}=\frac{1\times 10^{-5}}{1\times 10^{-3}}=\frac{1}{100}$

$100\times [H_3O^+]_{original}=[H_3O^+]_{final}$

From this we conclude that when the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is 100 times the original content.

Hence, the correct option is, (D) 100 times the original content.

7 0

3 years ago

Read 2 more answers

3/4(x-2)=x-1 please answer me

Elan Coil [88]

Answer:

-2

Explanation:

3/2 (x-2) = x-1

<=> 3/4 x - 3/2 = x-1

<=> 3/4 x - x = 3/2 -1