Answer:
Passive transport, and Active transport
Explanation:
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Answer:
T₂ = 43.46 °C
Explanation:
Given that:
The heat of the formation of carbon dioxide = - 393.5 kJ/mol (Negative sign suggests heat loss)
It means that energy released when 1 mole of carbon undergoes combustion = 393.5 kJ = 393500 J
Heat gain by water = Heat lost by the reaction
Thus,
For water:
Mass of water = 5100 g
Specific heat of water = 4.18 J/g°C
T₁ = 25 °C
T₂ = ?
Q = 393500 J
So,
T₂ = 43.46 °C
Particles that orbit the nucleus are called electrons.
Explanation: Electrons are negatively charged particles arranged in orbits around the nucleus of an atom and determining all of the atom's physical and chemical properties except mass and radioactivity.
Answer:
Compound B.
Explanation:
The freezing point depression is a colligative property. It depends on the number of particles (moles) present in the solution.

where b is the molal concentration

If m is constant (5 g), then

The compound with the greater molar mass has fewer moles and therefore fewer particles to depress the freezing point.
That must be Compound B, because Compound A has the lower freezing point.