The measure is the same. :)
Answer:
La configuración de estado fundamental del oro es [Xe]5d106s1 La diferencia de nivel de energía entre el 6s y el 5d es pequeña. Esto hace posible que uno de los dos electrones 6s esté en los orbitales 5d.
Explanation:
Answer:
The answer to your question is below
Explanation:
1)
Balanced chemical reaction
2CH₃OH + 3O₂ ⇒ 2 CO₂ + 4H₂O
Reactant Element Product
2 C 2
8 H 8
8 O 8
Molar mass of CH₃OH = 2[12 + 16 + 4]
= 2[32]
= 64 g
Molar mass of O₂ = 3[16 x 2] = 96 g
Theoretical proportion CH₃OH/O₂ = 64 g/96g = 0.67
Experimental proportion CH₃OH/O₂ = 60/48 = 1.25
Conclusion
The limiting reactant is O₂ because the Experimental proportion was higher than the theoretical proportion
2)
Balanced chemical reaction
S₈ + 12O₂ ⇒ 8SO₃
Reactant Elements Products
8 S 8
24 O 24
Molar mass of S₈ = 32 x 8 = 256 g
Molar mass of O₂ = 12 x 32 = 384 g
Theoretical proportion S₈ / O₂ = 256 / 384
= 0.67
Experimental proportion S₈ / O₂ = 40 / 35
= 1.14
Conclusion
The limiting reactant is O₂ because the experimental proportion was lower than the theoretical proportion.
Filling in the blanks, the full sentence is: Robert Boyle made the biggest impact on science by <span>writing out the scientific method for all of science.
</span><span>
The scientific method is the standard method of knowledge pursuit.</span><span> It involves careful observations,</span><span> formulating </span>hypotheses<span> (based on observations); preparation of </span>experimental<span> testing, and the measurement and interpretation of results</span>.
X= (3*2)(31.75)/(2*17)3*31.75/17
=5.603g H2
Answer: 5.603g H2
It’s all quite simple actually considering the fact the M(NH3) = 14 + 1*3 = 17g/mol
And M(H2) = 2*1 2g/mol
So 3H2 + N2 >> 2NH3
Givin that Xg is 31.75g
-HOPE THAT HELPED IN A WAY!!☺️
