In 0.190 mole of C6H14O, there is 0.190*6 (number of C in one molecule) = 1.140 mole of C atoms. The total number of C atoms = 1.14 * 6*
(atoms of C in one mole) = 6.84* atoms.
8. Which phrase best describes an atom?(A) a positive nucleus surrounded by a ha dnegative shell(B) a positive nucleus surrounde
d by a cl udof negative charges(C) a hard sphere with positive particlesuniformly embedded(D) a hard sphere with negative particlesuniformly embedded
1 answer:
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Answer:
- <u>Alkaline or basic solution </u>(alkaline and basic means the same)
Explanation:
According to the <em>pH</em>, solutions may be classified as neutral, acidic, or alkaline (basic).
This table shows such classification:
pH classification
7 neutral
> 7 alkaline or basic
< 7 acidic
Thus, since the pH of the solution is 8.3, which is greater than 7, the solution is classified as basic (alkaline).
Additionally, you must learn that pH is a logarithmic scale for the concentration of hydronium ions in the solution.
- pH = - log [H₃O⁺]
You can calculate the concentration of hydronium ions using antilogarithm properties:
NaOH solutions are alkaline solutions, bases, according to Arrhenius model, because they contain OH⁻ ions and release them when ionize in water.
Percent error is the difference between the measured and known value, divided by the known value, multiplied by 100%.
So first, we take our measured value, .299 cm, minus our known value, .225 cm.
.299 cm - .225 cm=.004 cm
Next, we divide that by our known value
Finally, multiply your answer by 100
.0177777778 x 100= 1.77777778 %
Round to three significant figures, and you're done.
=1.78 % error
Answer:
0.0714 M for the given variables
Explanation:
The question is missing some data, but one of the original questions regarding this problem provides the following data:
Mass of copper(II) acetate:
Volume of the sodium chromate solution:
Molarity of the sodium chromate solution:
Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:
Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:
Moles of the sodium chromate solution would be found by multiplying its volume by molarity:
Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.
Write the net ionic equation for this reaction:
Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:
According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:
The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate: