Answer:
2500 kb
Explanation:
Here, we are to calculate the bandwidth delay product
From the question, we are given that
band width = 500 Mbps
The bandwidth-delay product is = 500 x 10^6 x 25 x 10^-3
= 2500 Kbits
Answer:
The MSS is 1455
Explanation:
MSS or maximum segment size is the total number of data transferred minus the TCP and IP header. The total number of transmitted frames in a switch network is between 64 bytes to 1518 bytes with a header and trailer. The MSS does not exclude this data-link layer effect but only the transport layer like TCP and UDP, and IP address header, unlike the mtu (maximum transfer unit) which involves all headers.
