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Ksju [112]
3 years ago
7

Which set of three numbers could represent the lengths of the sides of a right triangle?

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0
Answer=5,12,13

Just plug all of these values into the pythagorean theorem. If they work, then they could represent a right triangle.

For example:
5²+12²=13²
25+144=169
169=169
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Subtract5x2 + 10x<br> 1 from 6x2<br> x + 3.
mixer [17]

Answer:

-6x^{3} +5x^{2} +10x+3

Step-by-step explanation:

5x^2+10x^1−6x^2x+3

=5x^2+10x+−6x^3+3

Answer:

=−6x^3+5x^2+10x+3

3 0
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What is the value of x to the nearest tenth?<br> 43°<br> 12<br> Х
daser333 [38]

Answer:

11.2

Step-by-step explanation:

tan 43 = x/12

x = 12 tan 43 = 11.19

6 0
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In Amy's garden the ratio of herbs to plants is 5:2. If there are 40 herb plants, how many vegetable plants are in her garden?
GREYUIT [131]
There are 16 vegetable plants because 40/5 is 8 and 2 times 8 is 16. 5:2=40:16
4 0
3 years ago
Which of the following expressions is equal to 1 divided by 16
Mama L [17]

Answer:

8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
After an extensive advertising campaign, the manager of a company expects the proportion of potential customers that recognize a
lina2011 [118]

Answer:

Step-by-step explanation:

Hello!

The study variable is:

X: number of customers that recognize a new product out of 120.

There are two possible recordable outcomes for this variable, the customer can either "recognize the new product" or " don't recognize the new product". The number of trials is fixed, assuming that each customer is independent of the others and the probability of success is the same for all customers, p= 0.6, then we can say this variable has a binomial distribution.

The sample proportion obtained is:

p'= 54/120= 0.45

Considering that the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal: p' ≈ N(p;\sqrt{\frac{p(1-p)}{n} })

The other conditions for this approximation are also met: (n*p)≥5 and (n*q)≥5

The probability of getting the calculated sample proportion, or lower is:

P(X≤0.45)= P(Z≤\frac{0.45-0.6}{\sqrt{\frac{0.6*0.4}{120} } })= P(Z≤-3.35)= 0.000

This type of problem is for the sample proportion.

I hope this helps!

5 0
2 years ago
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