All categories

2 years ago

Solve for x round to the nearest tenth

Mathematics

1 answer:

ludmilkaskok [199]2 years ago

7 0

Answer:

Step-by-step explanation:

1) 8.9

2) 27.8

3) 24.3

4) 11.4

5) 27.5

6) 49.2

7) 8.1
8)4.8

You might be interested in

I hate how i have to write things here

Harlamova29_29 [7]

Answer: Question 1 is m=-7/4

Question 2 is -4 as the y axis where it intercepts and the other coordinate is (3,-2)

Step-by-step explanation:

8 0

3 years ago

Kasih tau caranya dong

igor_vitrenko [27]

C . 250 cm^2

cause its the same

6 0

3 years ago

Find a polynomial function of degree 3 with 2, i, -i as zeros.

sergiy2304 [10]

Answer:

$p(x)= x^3-2x^2+x-2$

Step-by-step explanation:

Here we are given that a polynomial has zeros as 2 , i and -i . We need to find out the cubic polynomial . In general we know that if $\alpha , \ \beta \ \& \ \gamma$ are the zeros of the cubic polynomial , then ,

$\sf \longrightarrow p(x)= (x -\alpha )(x-\beta)(x-\gamma)$

Here in place of the Greek letters , substitute 2,i and -i , we get ,

$\sf\longrightarrow p(x)= (x -2 )(x-i)(x+i)$

Now multiply (x-i) and (x+i ) using the identity (a+b)(a-b)=a² - b² , we have ,

$\sf \longrightarrow p(x)= (x-2)\{ x^2 - (i)^2\}$

Simplify using i = √-1 ,

$\sf \longrightarrow p(x)= (x-2)( x^2 + 1 )$

Multiply by distribution ,

$\sf \longrightarrow p(x)= x(x^2+1) -2(x^2+1)$

Simplify by opening the brackets ,

$\sf\longrightarrow p(x)= x^3+x-2x^2-2$

Rearrange ,

$\sf\longrightarrow \underline{\boxed{\blue{\sf p(x)= x^3-2x^2+x-2}}}$

4 0

2 years ago

I need help remembering the steps to solve for 3x-7>2

goblinko [34]

3x-7>2
add 7 to both sides: 3x>9
divide both sides by 3: x>9

7 0

3 years ago

Read 2 more answers

Is this correct???? TYSM

vfiekz [6]

Yep, this is all correct!

-6/2 = y/4

y = (-6×4)/2

y = -24/2

y = -12

x was multiplied by 2

and y was also multiplied by 2

5 0

3 years ago