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2 years ago

14

Explain how to describe the data on a histogram.

2 answers:

AnnZ [28]2 years ago

8 0

A histogram is a graphical representation of discrete or continuous data. To put it another way, it gives a visual representation of numerical data by displaying the amount of data points that fall within a given range of values.

IrinaVladis [17]2 years ago

6 0

Answer:

visual interpretation. of numerical data

Step-by-step explanation:

A histogram is a graphical representation of discrete or continuous data. To put it another way, it gives a visual representation of numerical data by displaying the number of data points that fall within a given range of values.

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Which expression is equivalent to 1/6 - 3/8 + 1/2

serg [7]

Answer:

7/24

Step-by-step explanation:

1/6-3/8+1/2

4/24-9/24+12/24

-5/24+12/24

7/24

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2 years ago

Calculate the area of a square with a side length of 12 cm.

inna [77]

Answer:

24 cm squared

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

If a,b,c,d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)(x+d)(x^2+ex+1), what is the value of a+b+c+d+e?

Irina18 [472]

Answer:

36

Step-by-step explanation:

Hello,

If $X=x^2$ it becomes

$X^3-289X^2-X+289=(X^2-1)(X-289)$

and $289=17^2$

$X^2-1=(X-1)(X+1)=(x^2-1)(x^2+1)=(x+1)(x-1)(x^2+1) \\\\x^2-289=x^2-17^2=(x-17)(x+17)$

So,

$x^6-289x^4-x^2+289=(x^2-1)(x^2+1)(x^2-289)=(x-1)(x+1)(x+17)(x-17)(x^2+1)$

a = 1

b = 1

c = 17

d = 17

e = 0

Then a + b + c + d + e = 36

Thanks

3 0

3 years ago

Can someone do this for me thanks ok bye

Dvinal [7]

Answer:

log2 10 = 3x

Step-by-step explanation:

Basic Logarithm Tenets

7 0

3 years ago

Read 2 more answers

a 34 gram sample of a substance that's used to treat thyroid disorders has a k-value of 0.137. find the substance's half-life, i

Ira Lisetskai [31]

Answer:

5.1 days

Step-by-step explanation:

Given in the question,

initial amount of substance = 34 grams

k-value = 0.137

To find the half life of this substance we will use following formula

$N(0)/2 = N(0)e^{-kt}$

here N(0) is initial amount of substance

t is time in days

Plug values in the formula

$34 /2 = 34e^{-0.137t}$

1/2 = e^{-0.137t}

Take logarithm on both sides

ln(1/2) = ln( e^{-0.137t})

ln(1/2) = -0.137t

t = ln(1/2) / -0.137

t = 5.059

t ≈ 5.1 days (nearest to tenths)

3 0

3 years ago