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Ahat [919]
2 years ago
14

Explain how to describe the data on a histogram.

Mathematics
2 answers:
AnnZ [28]2 years ago
8 0
A histogram is a graphical representation of discrete or continuous data. To put it another way, it gives a visual representation of numerical data by displaying the amount of data points that fall within a given range of values.
IrinaVladis [17]2 years ago
6 0

Answer:

 visual interpretation. of numerical data

Step-by-step explanation:

A histogram is a graphical representation of discrete or continuous data. To put it another way, it gives a visual representation of numerical data by displaying the number of data points that fall within a given range of values.

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Answer:

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Step-by-step explanation:

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businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
Write 6 2/3 as a improper fraction
kirill115 [55]
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ivann1987 [24]
7+(-9)+6+(-10)+(-13)+(-5)=
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mean is the sum of all the numbers divided by the total number of numbers within the data.

-24÷6=-4

The mean is -4.
5 0
3 years ago
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