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DaniilM [7]
2 years ago
10

GIVING AWAY 100 POINTS!!! BE THE FIRST TWO

Mathematics
2 answers:
Lelu [443]2 years ago
5 0

Answer:

Thank you!!!

Step-by-step explanation:

kipiarov [429]2 years ago
5 0

Answer:

i have 26938 points

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I dont know what to do
Margarita [4]
It is -12<n<-11 so it is between that
5 0
3 years ago
the function y=-2(x-3)^2+4 shows the daily profit (in hundreds of dollars) of a hot dog stand wherex is the price of a hot dog (
Pavlova-9 [17]

Step-by-step explanation:

y=-2(x-3)^2+4

To interpret the zeros of this function , put y =0

0=-2(x-3)^2+4

0+2(x-3)^2=4

2(x-3)^2=4

(x-3)^2=\frac{4}{2}

(x-3)^2=2

Taking square root on both sides:

(x-3)=\pm \sqrt{2}

So, we got values of x :

1) x=3+\sqrt{2}=1.59

2) x=3-\sqrt{2}=4.41

This means the person will have profit if price of a hot dog ranges from $1.59 to $4.41.

8 0
3 years ago
Why is this picture an example of a physical change<br> Plzzzz help
Montano1993 [528]

Answer:

No new substance is being formed.

6 0
3 years ago
Read 2 more answers
The thickness X of aluminum sheets is distributed according to the probability density function f(x) = 450 (x2 - x) if 6 &lt; x
grandymaker [24]

Solution :

Given :

f(x) = \left\{\begin{matrix}\frac{1}{450}(x^2-x) & \text{if  } 6 < x < 12 \\ 0 & \text{otherwise}\end{matrix}\right.

1. Cumulative distribution function

$P(X \leq x) = \int_{- \infty}^x f(x) \ dx$

              $=\int_{- \infty}^6 f(x) dx + \int_{6}^x f(x) dx $

             $=0+\int_6^x \frac{1}{450}(x^2-x) \ dx$

             $=\frac{1}{450} \int_6^x (x^2-x) \ dx$

             $=\frac{1}{450}\left[\frac{x^3}{3}-\frac{x^2}{2}\right]_6^x$

             $=\frac{1}{450}\left[ \left( \frac{x^3}{3} - \frac{x^2}{2}\left) - \left( \frac{6^3}{3} - \frac{6^2}{2} \right) \right]  $

            $=\frac{1}{450}\left[\frac{x^3}{3} - \frac{x^2}{2} - 54 \right]$

2.  Mean $E(x) = \int_{- \infty}^{\infty} \ x \ f(x) \ dx$

                       $=\int_{6}^{12}x . \left( \frac{1}{450} \ (x^2-x)\right)\  dx$

                     $=\frac{1}{450} \int_6^{12} \ (x^3 - x^2) \ dx$

                     $=\frac{1}{450} \left[\frac{x^4}{4} - \frac{x^3}{3} \right]_6^{12} \ dx$

                     $=\frac{1}{450} \left[ \left(\frac{(12)^4}{4} - \frac{(12)^3}{3} \right) -  \left(\frac{(6)^4}{4} - \frac{(6)^3}{3} \right) $

                     $=\frac{1}{450} [4608 - 252]$

                    = 17.2857

5 0
3 years ago
I'll give brainliest!!! I need help fast please I just need someone to check my answers!!! Don't respond if you don't know what
olga2289 [7]

Answer:

your correct

Step-by-step explanation:

:D

3 0
3 years ago
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