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balandron [24]
3 years ago
11

"A certain group one metal combines with Hydrogen, to form a molecule with the formula XH. The equilibrium bond length of this c

ompound is 1.5957 Å. If this molecule exhibits a pure rotational spectrum with a rotational constant of 7.5131cm−1, calculate the molecular weight of metal X."
I thought that you would use a mix of the reduced mass and rotational constant formulas to get:

1.66e-27(\frac{(m1)(m2)}{m1+m2})=\frac{h/2\pi}{4\pi Bcr^{2} }

However, that just gives a negative answer, and mass cannot be negative. I am confused and would appreciate any help
Chemistry
1 answer:
Tasya [4]3 years ago
5 0

Based on the bond length, the molecular weight of the unknown metal X is 23.

<h3>What are ionic compounds?</h3>

Ionic compounds are compounds which are formed between oppositely charged ions.

When hydrogen combines with the group 1 metals, they form ionic compounds.

The group one metals that combine with hydrogen to firm ionic bonds include:

  • Lithium to give Lithium hydride with equilibrium bond length of 0.239Å.
  • Sodium to give sodium hydride with equilibrium bond length of 1.896Å.
  • Potassium to give potassium hydride with equilibrium bond length of 2.321Å

The molecular weight of lithium is 7 g

The molecularweight of sodium is 23

The molecular weight of Potassium is 39.

Therefore, based on the equilibrium bond length, the molecular weight of the unknown metal X is 23.

Learn more about bond length at: brainly.com/question/3405662

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Answer:

3.35 atm

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Explanation:

Step 1: Given data

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Step 2: Calculate the final pressure of butane gas

If we assume ideal behavior, we can calculate the final pressure of butane gas using Gay Lussac's law.

P₁/T₁ = P₂/T₂

P₂ = P₁ × T₂/T₁

P₂ = 2.50 atm × 393 K/293 K = 3.35 atm

Since P₂ > 3.00 atm, the lighter would explode.

6 0
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The resonance forms of O3 are attached as an image.

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