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scoray [572]
4 years ago
13

How many atoms are in 4 mol Zn?

Chemistry
1 answer:
Brut [27]4 years ago
6 0
To covert from moles to atoms times the number of moles by Avogadro's Number (6.022×10²³)

4.0 × 6.022×10²³ = 2.4088×10^24
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An omnivore eats what kind of food
skelet666 [1.2K]
Omnivores eat both plants and animals. Carnivores only eat animals and herbivores only eat plants.
3 0
3 years ago
Read 2 more answers
What are the coefficients that would balance this equation? ___ HCL+___ NaOH-___ NaCl+____ H20
nexus9112 [7]

Answer:

It's already balanced as the equation has the same number of atoms on both left and right side

8 0
2 years ago
A 170.0 g sample of an unidentified compound contains 29.84 g sodium, 67.49
GREYUIT [131]

The empirical formula : Na₂Cr₂O₇

<h3>Further explanation</h3>

Given

170 g sample contains :

29.84 g sodium, 67.49  g chromium, and 72.67 g oxygen

Required

The compound's empirical formula

Solution

mol ratio of elements :

Na : 29.84 : 23 g/mol = 1.297

Cr : 67.49 : 51,9961 g/mol = 1.297

O : 72.67 : 16 g/mol = 4.54

Divide by 1.297

Na : Cr : O = 1 : 1 : 3.5 = 2 : 2 : 7

6 0
3 years ago
When nitrogen gas (N2) reacts with hydrogen gas(H) ammonia gas (NH3) is formed. How many grams of hydrogen gas are required to r
kupik [55]

Mass of Hydrogen gas required to react : 0.936 g

<h3>Further explanation</h3>

Reaction on Nitrogen gas and Hydrogen gas to produce Ammonia gas

N₂ (g) + 3 H₂ (g) ⇒ 2 NH₃ (g)

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol

so mol Nitrogen for 3.5 L at STP :

\tt mol=\dfrac{3.5~L}{22.4~L}=0.156

From the equation, mol ratio of N₂ : H₂ = 1 : 3, so mol H₂ :

\tt \dfrac{3}{1}\times 0.156=0.468

then mass of Hydrogen(MW= 2 g/mol) :

\tt mass=mol\times MW\\\\mass=0.468\times 2\\\\mass=0.936~g

7 0
3 years ago
If you wanna get oil to 180 celcius when it starts at 20 how many units of thermal energy is needed?
Zarrin [17]

Answer:

The thermal energy (heat) needed, to raise the temperature of oil of mass  'm' kilogram and specific heat capacity 'c' from 20°C to 180°C  is  160·m·c joules

Explanation:

The heat capacity, 'C', of a substance is the heat change, ΔQ, required by a given mass, 'm', of the substance to produce a unit temperature change, ΔT

∴ C = ΔQ/ΔT

ΔQ = C × ΔT

C = m × c

Where;

c = The specific heat capacity

ΔT = The temperature change = T₂ - T₁

∴ ΔQ = m × c × ΔT

Therefore, the thermal energy (heat) needed, ΔQ, to raise the temperature of oil of mass 'm' kilogram and specific heat capacity, 'c' from 20°C to 180°C  is given as follows;

ΔQ = m × c × (180° - 20°) = 160° × m·c

ΔQ = 160·m·c joules

7 0
3 years ago
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