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Alenkasestr [34]
2 years ago
11

Find the angle of x please!

Mathematics
1 answer:
frutty [35]2 years ago
6 0

Check the picture below.

Make sure your calculator is in Degree mode.

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What is the slope of the line that goes through -3,7 & -17,3
Natalka [10]

Point 1: (-3, 7)

Point 2: (-17, 3)

To find the slope, we need to use the slope formula which is as follows: m = (y2 - y1) / (x2 - x1). We will plug in each x and y coordinate from our points above, respectively.

m = (3 - 7) / (-17 - - 3)

m = (-4) / (-14)

m = 2/7

The slope of the line that goes through (-3, 7) and (-17, 3) is 2/7.

Hope this helps!! :)

7 0
3 years ago
Which equation results from adding the equations in this system?
MArishka [77]

Answer:

8y = -6

Step-by-step explanation:

x + 6y -x +2y = 9 +(-15) ➡ 8y = -6

5 0
3 years ago
Need help with this one
Simora [160]

Answer:

try c

Step-by-step explanation:

6 0
3 years ago
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Can anyone help me with this please and ty I really appreciate it if u can
Anarel [89]
Your riiiiiiiiiiuiuuiii
8 0
3 years ago
Use the quadratic function f(x) = 2x^2 + 4x - 15. Find any x intercepts.
8_murik_8 [283]

So for this function we will be using the quadratic formula, which is x=\frac{-b+\sqrt{b^2-4ac}}{2a},\frac{-b-\sqrt{b^2-4ac}}{2a} , to solve. a = x^2 coefficient, b = x coefficient, and c = constant. Using our equation, we can solve for the zeros (x-intercepts) as such:

x=\frac{-4+\sqrt{4^2-4*2*(-15)}}{2*2},\frac{-4-\sqrt{4^2-4*2*(-15)}}{2*2}\\ \\ x=\frac{-4+\sqrt{16-(-120)}}{4},\frac{-4-\sqrt{16-(-120)}}{4}\\ \\ x=\frac{-4+\sqrt{136}}{4},\frac{-4-\sqrt{136}}{4}\\ \\ x=1.92,-3.92

In short, your x-intercepts (rounded to the hundredths) are (1.92,0) and (-3.92,0).

6 0
4 years ago
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