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2 years ago

Put 3/5 as a decimal and is it a terminating or repeating decimal?

Mathematics

1 answer:

pickupchik [31]2 years ago

6 0

Answer:

3/5 as a decimal is 0.6 and it is terminating not repeating

Step-by-step explanation:

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Find the value of x. log x 8 = 0.5 A. 4 B. 16 C. 32 D. 64

Lisa [10]

The answer is D. 64. Have a nice day!

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2 years ago

State whether the linear equations in each pair are parallel, perpendicular,or neither.

posledela

All I know is they can’t be parallel because they don’t have the same gradient. I don’t think they are perpendicular either but don’t fully trust me on that

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2 years ago

Read 2 more answers

What is the area of this shape?

m_a_m_a [10]

Step-by-step explanation:

idk the answer but find the area of a circle with the radius of 45 m and then find the area of the rectangle then add them together.

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2 years ago

Simplify expression x8y-26/x14y-5 × x-39y-21

koban [17]

The simplified form of the expression is $x^{-45} y^{-42}$

<h3>Simplifying an expression</h3>

From the question, we are to simplify the given expression

The given expression is

$\frac{x^{8}y^{-26} }{x^{14}y^{-5} } \times x^{-39} y^{-21}$

The expression can be simplified as shown below

$\frac{x^{8}y^{-26} }{x^{14}y^{-5} } \times x^{-39} y^{-21}$

$\frac{x^{8} \times x^{-39} \times y^{-26} \times y^{-21} }{x^{14} \times y^{-5} }$

$\frac{x^{8+-39} \times y^{-26+-21} }{x^{14} \times y^{-5} }$

$\frac{x^{8-39} \times y^{-26-21} }{x^{14} \times y^{-5} }$

$\frac{x^{-31} \times y^{-47} }{x^{14} \times y^{-5} }$

Then,

$\frac{x^{-31} }{x^{14} } \times \frac{ y^{-47} }{ y^{-5} }$

$x^{-31-14} \times y^{-47--5}$

$x^{-31-14} \times y^{-47+5}$

$x^{-45} \times y^{-42}$

$x^{-45} y^{-42}$

Hence, the simplified form of the expression is $x^{-45} y^{-42}$

Learn more on Simplifying an expression here: brainly.com/question/2320607

#SPJ1

3 0

1 year ago

What is the quotient in the polynomial form?

Oxana [17]

First step of a synthetic divison is that we need to carry down the leading coefficient. Here the leading coefficient is 2. So, carry down 2 at the bottom.

Next step is to multiply the divisor -3 with this carry down number 2. So, we have got 3*(-2)= -6 which will place atthe bottom of the next coefficient 4.

Next step is to add this column.

Now repeat the same method again till the last colum.

At the end we have got 0 after the addition. Which means the remainder is 0.

So, the quotient is 2x^2-2x+2.

8 0

2 years ago