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lara31 [8.8K]
3 years ago
6

2)Using the properties of similar triangles, input the values that you know the measurements of and use properties of similar tr

iangles to indirectly measure 5 objects of your own choice. Show your work.
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Similar triangles may or may not have congruent sides lengths

<h3>How to determine the measurements of the objects</h3>

From the properties of similar triangles, the side lengths of similar triangles may or may not be congruent, but the side lengths are always proportional.

Take for instance, an equilateral triangle has a dimension of 2cm by 2cm by 2cm

The similar triangles could have the following dimensions:

  • 3cm by 3cm by 3cm
  • 4cm by 4cm by 4cm
  • 6cm by 6cm by 6cm
  • 7cm by 7cm by 7cm
  • 10cm by 10cm by 10cm

This is so because the triangles are proportional to the equilateral triangle

Read more about similar triangles at:

brainly.com/question/14285697

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If angle DEF is an isosceles triangle with DE congruent to EF, Find x
Oduvanchick [21]

Answer:

Fourth choice, 16

Step-by-step explanation:

The 2 angles are both 74 degrees, so the side that is facing each angle will be the same length, so:

9x - 73 = 3x + 23

add 73 to both sides

9x = 3x + 96

subtract 3x from both sides

6x = 96

divide by 6

x = 16

7 0
3 years ago
How many 8s go into 293 cause i cant work it out so far?
ratelena [41]
Try multiplying it
we know that 8 times 10=80 so multiply 80 by 2, then 3 then 4 untill you get close to that number so
80 times 2=160
80 times 3=240
80 times 4=320
this is over so it is more than 30 8's but less than 40 8's
so start from 320
subtract 293 from 320
320-293=27
divide 27 by 8
27/8=3 and 3/8
add that to 30

33 and 3/8 8's will fit

the teacher probably wants how many whole 8's can fit so get rid of the 3/8 and just put 33 8's
4 0
4 years ago
Solve <br> Z-8/4=-1<br><br> 1. Z= -12<br><br> 2. Z= 28<br><br> 3. Z= 4<br><br> 4. Z= -36
Gnesinka [82]

Answer:

3

Step-by-step explanation:


8 0
3 years ago
Can’t afford to get wrong please do not write if you don’t know thanks !
Katena32 [7]
You don't need to understand the construction or why it works. You only need to accept the fact that it does. You can figure out the answers to this question by looking at the picture.

RT is tangent to circle Q -- TRUE. That is the point of the construction.

QT is a radius of circle Q -- TRUE. Q is the center and T is on the circle. A line segment from the center to a point on the circle is a radius.

m∠QSR = 90° -- FALSE. Those points lie on the same line. The measure of the angle is 180°.

QS = QT -- FALSE. S lies inside circle Q, so is closer to the center than T, which lies on the circle. (For some choice of point R, S might lie on the circle, but because this statement is not always true, it must be considered false.)

ΔRTQ is a right triangle -- TRUE. A tangent line is always perpendicular to the radius to the point of tangency. The construction succeeds because RTQ is inscribed in semicircle RTQ (centered at S). Such a triangle is always a right triangle.
3 0
4 years ago
Notes on how to multiply/divide with scientific notation
snow_tiger [21]

Answer:

Treat the numbers separately and powers separately.

Multiply the two results at the end.

Example:

(2×10⁵) ÷ (4×10²)

(2 ÷ 4) × (10⁵ ÷ 10²)

0.5 × 10³

5.0 × 10²

3 0
3 years ago
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