We know that
a(n)=4n+1
To find the sum of the first n<span> terms of an arithmetic series
use the formula
</span><span><span>Sn</span>=<span>n(<span>a1</span> + <span>an</span>)/2
</span></span>a1--------------> is the first term
an--------------> is the last term
n--------------- > <span>is the number of terms
</span>we have that
a1------------> 4*(1)+1=5
a30----------> 4*(30)+1=121
n------------- > 30
S30=30*(5 + 121)/2=1890
the answer is 1890
The maximum height is 20 yards and the total horizontal distance is 36 yards, which is the distance between the point (2, 0) and (38, 0).
<h3>What is a parabola?</h3>
It is defined as the graph of a quadratic function that has something bowl-shaped.
We have:
The blackbird starts his flight path from (2, 0). His flight path reaches a maximum height of 20 yards and lands at point (38, 0).
Here the bird path will be a parabola with a maximum height of 20 yards.
The total horizontal distance traveled by the bird = The distance between the points (2, 0) and (38, 0)
= √(38-2)²
= 36 yards
Thus, the maximum height is 20 yards and the total horizontal distance is 36 yards, which is the distance between the point (2, 0) and (38, 0).
Learn more about the parabola here:
brainly.com/question/8708520
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Answer:
The correct option is C:
C) The representative sample contained more girls than boys.
Step-by-step explanation:
It is given that a random sample is chosen from a total students of 160 students. The sample can be of 10,15 or any small numbers of students as compared to 160. However, a sample cannot be of 160 students as it is defined as a population in this case.
A random sample is always unbiased. Which means that the sample chosen should have around the same proportion of girls to boys as it is in the population of 160.
We know that:
Total boys in 160 = 65
Total girls in 160 = 95
Proportion of girls to boys = 95/65 = 1.462
Which means that for every 1 boy, there are 1.462 of girls.
The same ratio is held in a random sample, hence the total number of girls will be greater than boys
??? Where’s the rest of that problem