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Maru [420]
1 year ago
12

After rubbing a balloon on your shirt, your hair sticks up when the balloon is near your head. Explain how tiny particles on you

and the balloon can make your hair stand up. (1 point) Protons are transferred from your body to the balloon. This gives you a negative charge and the balloon a positive charge. The opposite charges attract. Electrons are transferred from your body to the balloon. This gives you and the balloon a negative charge. The like charges attract. Electrons are transferred from your body to the balloon. This gives you a positive charge and the balloon a negative charge. The opposite charges attract. Electrons are transferred from your body to the balloon. This gives you a negative charge and the balloon a positive charge. The opposite charges attract.​
Physics
1 answer:
skad [1K]1 year ago
3 0
Almost right. protons are positive and electrons are negative. so when you run the balloon on your hair, electrons are transferred between them (i’m not sure which direction) and now one is positively charged as it lost negative particles and one is negative as it gained negative particles (electrons). opposite charges attract
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Unpolarized light with intensity 300 W m2 is incident on three polarizers, P1, P2, and P3 numbered in the order light reaches th
sweet [91]

Answer:

answer is A corresponding to 60 W

Explanation:

The polarization phenomenon is descriptor Malus's law

      I = I₀ cos² θ

Where I and Io are the transmitted and incident intensities, respectively, θ  is the angle between the direction of polarization of the light and the polarizer.

Unpolarized light strikes the first polarizer and half of it is transmitted, which has the polarization direction of the polarizer

      I₁ = ½ I₀

      I₁ = ½ 300

      I₁ = 150 W

The transmission by the second polarizer (P2) is

      I₂ = I₁ cos² θ 1

      I₂ = 150 cos² 45

      I₂ = 75 W

The transmission of the third polarizer (P3)

     I₃ = I₂ cos² θ 2

     I₃ = 75 cos² 30

     I₃ = 56.25 W

This is the light transmitted by the 56 W system, the closest answer is A corresponding to 60 W

7 0
2 years ago
Moustapha jones drives east at 100km/hr for 3 hours then back west at 80km/hr for 1.5 hours. which pair of answers gives his ave
olya-2409 [2.1K]

The average speed of the car is 93.33 km/hr and the average velocity of the car is 40 km/hr.

The total distance cover in east direction is=100*3=300 km

The total distance cover in the west direction=80*1.5=120 km

The total distance covered is =300+120=420 km

And Total displacement of the car is =300-120=180 km

As we know that the average speed is given as

Avg Speed =Total Distance / Total time

=420/4.5=93.33 km/hr

As we know that the average velocity is given as

Avg Speed =Total Displacement/ Total time

=180/4.5=40 km/hr

Therefore, The average speed of the car is 93.33 km/hr and the average velocity of the car is 40 km/hr.

7 0
3 years ago
Good science does not depend on interactions within the scientific community true or false
vlabodo [156]

Answer:

I would say that is false. Science can only be perfect after at least some sort of scientific communication and interaction.

6 0
2 years ago
"A 78-year-old woman has a mean arterial pressure of 120 mm Hg and a heart rate of 60 beats/min. She has a stroke volume of 50 m
aivan3 [116]

Answer:

0.04 mm Hg / mL / min .

Explanation:

Arterial pressure = 120 mm Hg

right atrial pressure = 0 mm Hg

Drop in pressure due to peripheral resistance = 120 mm Hg

volume of cardiac output per minute = 3000 mL/min

total  peripheral resistance

= 120 / 3000 mm Hg / mL / min

= 0.04 mm Hg / mL / min .

8 0
3 years ago
A 2800 kg truck moving at 12 m/s to the right hits a stopped 1100 kg car. What is the combined velocity the moment they stick to
leva [86]

Answer:

The combined velocity is 8.61 m/s.

Explanation:

Given that,

The mass of a truck, m = 2800 kg

Initial speed of truck, u = 12 m/s

The mass of a car, m' = 1100 kg

Initial speed of the car, u' = 0

We need to find the combined velocity the moment they stick together. Let it is V. Using the conservation of momentum.

m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}\\\\V=\dfrac{2800\times 12+0}{2800+1100}\\\\V=8.61\ m/s

So, the combined velocity is 8.61 m/s.

5 0
2 years ago
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