Answer:
Explanation:
Since the roundabout is rotating with uniform velocity ,
input power = frictional power
frictional power = 2.5 kW
frictional torque x angular velocity = 2.5 kW
frictional torque x .47 = 2.5 kW
frictional torque = 2.5 / .47 kN .m
= 5.32 kN . m
= 5 kN.m
b )
When power is switched off , it will decelerate because of frictional torque .
Answer:
The value is
Explanation:
From the question we are told that
The wavelength is ![\lambda = 48.2 nm = 48.2 *10^{- 9 }\ m](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20%2048.2%20nm%20%20%3D%20%2048.2%20%20%2A10%5E%7B-%209%20%7D%5C%20%20m)
The velocity is ![v = 2.371*10^6 \ m/s](https://tex.z-dn.net/?f=v%20%3D%202.371%2A10%5E6%20%5C%20m%2Fs)
The mass of electron is ![m_e = 9.109*10^{-31} \ kg](https://tex.z-dn.net/?f=m_e%20%20%3D%20%209.109%2A10%5E%7B-31%7D%20%5C%20%20kg)
Generally the energy of the incident light is mathematically represented as
![E = \frac{h * c}{\lambda}](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7Bh%20%2A%20%20c%7D%7B%5Clambda%7D)
Here c is the speed of light with value
h is the Planck constant with value ![h = 6.62607015 * 10^{-34 } J\cdot s](https://tex.z-dn.net/?f=h%20%3D%206.62607015%20%2A%20%2010%5E%7B-34%20%7D%20%20J%5Ccdot%20s)
So
![E = \frac{6.62607015 * 10^{-34 }* 3.0 *10^{8}}{48.2 *10^{- 9 }}](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7B6.62607015%20%2A%20%2010%5E%7B-34%20%7D%2A%203.0%20%2A10%5E%7B8%7D%7D%7B48.2%20%20%2A10%5E%7B-%209%20%7D%7D)
=> ![E = 4.12 *10^{-18} \ J](https://tex.z-dn.net/?f=E%20%3D%204.12%20%2A10%5E%7B-18%7D%20%5C%20%20J%20)
Generally the kinetic energy is mathematically represented as
![E_k = \frac{1}{2} * m_e * v^2](https://tex.z-dn.net/?f=E_k%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20%20m_e%20%2A%20v%5E2)
=> ![E_k = \frac{1}{2} * 9.109*10^{-31} * (2.371*10^6 )^2](https://tex.z-dn.net/?f=E_k%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20%209.109%2A10%5E%7B-31%7D%20%2A%20%282.371%2A10%5E6%20%29%5E2)
=> ![E_k = 2.56 *0^{-18} \ J](https://tex.z-dn.net/?f=E_k%20%20%3D%20%202.56%20%2A0%5E%7B-18%7D%20%5C%20%20J%20)
Generally the ionization energy is mathematically represented as
![E_i = 4.12 *10^{-18} - 2.56 *0^{-18}](https://tex.z-dn.net/?f=E_i%20%20%3D%20%204.12%20%2A10%5E%7B-18%7D%20-%20%20%202.56%20%2A0%5E%7B-18%7D)
=>
Answer:
2 seconds
Explanation:
The function of height is given in form of time. For maximum height, we need to use the concept of maxima and minima of differentiation.
![h(t)=-16t^{2}+64t+112](https://tex.z-dn.net/?f=h%28t%29%3D-16t%5E%7B2%7D%2B64t%2B112)
Differentiate with respect to t on both the sides, we get
![\frac{dh}{dt}=-32t+64](https://tex.z-dn.net/?f=%5Cfrac%7Bdh%7D%7Bdt%7D%3D-32t%2B64)
For maxima and minima, put the value of dh / dt is equal to zero. we get
- 32 t + 64 = 0
t = 2 second
Thus, the arrow reaches at maximum height after 2 seconds.
The answer is A. The outer lines change as it moves
The two ladybugs have same rotational (angular) speed
Explanation:
The rotational (angular) speed of an object in circular motion is defined as:
![\omega=\frac{\theta}{t}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B%5Ctheta%7D%7Bt%7D)
where
is the angular displacement
t is the time interval considered
Here we have two ladybugs, which are located at two different distances from the axis. In particular, ladybug 1 is halfway between ladybug 2 and the axis of rotation. However, since they rotate together with the disk, and the disk is a rigid body, every point of the disk cover the same angle
in the same time
: this means that every point along the disk has the same angular speed, and therefore the two ladybugs also have the same angular speed.
On the other hand, the linear speed of the two ladybugs is different, because it follows the equation:
![v=\omega r](https://tex.z-dn.net/?f=v%3D%5Comega%20r)
where r is the distance from the axis: and since the two ladybugs are located at different
, they have different linear speed.
Learn more about circular motion:
brainly.com/question/2562955
brainly.com/question/6372960
#LearnwithBrainly