1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
postnew [5]
1 year ago
5

Question 3(Multiple Choice Worth 3 points)

Physics
1 answer:
Burka [1]1 year ago
8 0

The unit of measurement used in the metric system is  Meters.

The metric system makes use of measurements that we often see every day. these are used to measure length, weight, and capability. you will often see these as grams, kilograms, millimetres, centimeters, meters, milliliters, and liters. The metric machine is used all around the globe as it is easy to understand.

The metric system is a system of measurement that succeeded the decimalized system primarily based on the meter that had been added in France in the 1790s.

Metrics are measures of quantitative assessment normally used for comparing and tracking performance or manufacturing. Metrics may be used in a ramification of situations. Metrics are heavily trusted in the monetary evaluation of corporations with the aid of each inner manager and external stakeholders.

Learn more about the metric system here:-brainly.com/question/1837503

#SPJ9

You might be interested in
Yoga not only builds flexibility, but strength and balance.<br><br> True or False
azamat

Answer:

True

Explanation:

I just know.

3 0
3 years ago
Will give correct answer brainliest
levacccp [35]
The potential energy= mass times gravity times height. However, we are missing height. Gravity is a constant that is 9.8 on Earth. We then solve for height by dividing 350 by 10 and then 9.8 to get about 3.5.
TLDR: 3.5
3 0
3 years ago
Read 2 more answers
When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 49.
UkoKoshka [18]

Answer:

1.1397 Nm

Explanation:

When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth.

If the muscle generates a force

F =  49.5 N and r = 2.65 cm , then the torque is equal to rF

we see that r = 2.65 cm = 0.0265 m

therefore

torque = 0.0265 x 49.5

= 1.1397 Nm

4 0
3 years ago
Assuming that each nucleus is roughlyspherical and that its mass is roughly equal to A (in atomic mass units {\rm u}), what is t
lara [203]

Answer:

ρ/ρ2 = 3 / R₀       the two densities are different

Explanation:

Density is defined as

       ρ = M / V

As the nucleus is spherical

       V = 4/3 π r³

Let's replace

      ρ = A / (4/3 π R₀³)

      ρ = ¾ A / π R₀³

b)

      ρ2 = F / area

The area of ​​a sphere is

     A = 4π R₀²

     ρ2 = F / 4π R₀²

     ρ2 = F / 4π R₀²

Atomic number is the number of protons in the nucleon in not very heavy nuclei. This number is equal to the number of neutrons, but changes in heavier nuclei, there are more neutrons than protons.

Let's look for the relationship of the two densities

     ρ/ρ2 = ¾ A / π R₀³ / (F / 4π R₀²)

     ρ /ρ2 = 3 (A / F) (1 / R₀)

In this case it does not say that the nucleon number is A (F = A), the relationship is

     ρ/ρ2 = 3 / R₀

I see that the two densities are different

3 0
3 years ago
Determine the CM of a rod assuming its linear mass density λ (its mass per unit length) varies linearly from λ = λ0 at the left
Dahasolnce [82]

Answer:

x_c= \dfrac{5}{9}L

I=\dfrac {7}{12}\lambda_ 0 L^3

Explanation:

Here mass density of rod is varying so we have to use the concept of integration to find mass and location of center of mass.

At any  distance x from point A mass density

\lambda =\lambda_0+ \dfrac{2\lambda _o-\lambda _o}{L}x

\lambda =\lambda_0+ \dfrac{\lambda _o}{L}x

Lets take element mass at distance x

dm =λ dx

mass moment of inertia

dI=\lambda x^2dx

So total moment of inertia

I=\int_{0}^{L}\lambda x^2dx

By putting the values

I=\int_{0}^{L}\lambda_ ox+ \dfrac{\lambda _o}{L}x^3 dx

By integrating above we can find that

I=\dfrac {7}{12}\lambda_ 0 L^3

Now to find location of center mass

x_c = \dfrac{\int xdm}{dm}

x_c = \dfrac{\int_{0}^{L} \lambda_ 0(1+\dfrac{x}{L})xdx}{\int_{0}^{L} \lambda_0(1+\dfrac{x}{L})}

Now by integrating the above

x_c=\dfrac{\dfrac{L^2}{2}+\dfrac{L^3}{3L}}{L+\dfrac{L^2}{2L}}

x_c= \dfrac{5}{9}L

So mass moment of inertia I=\dfrac {7}{12}\lambda_ 0 L^3 and location of center of mass  x_c= \dfrac{5}{9}L

8 0
3 years ago
Other questions:
  • Why does a balloon stick to a wall questions and problems answers?
    9·1 answer
  • Which of the following best explains why cells remove waste?
    15·2 answers
  • slader A steel bar is 150 mm square and has a hot-rolled finish. It will be used in a fully reversed bending application. Sut fo
    7·1 answer
  • A woman performs 2000 J of work in order to push a cart full of groceries 50 meters. How much force did she apply to the cart?
    13·1 answer
  • Are the correct? PLEASE HELP ASAP
    10·2 answers
  • How much work did the movers do (horizontally) pushing a 46.0-kgkg crate 10.5 mm across a rough floor without acceleration, if t
    13·1 answer
  • A resistor R and a capacitor C are connected in series to a battery of terminal voltage V0. Which of the following equations rel
    7·1 answer
  • What is CHA-CHA-CHA.​
    6·1 answer
  • A ball is thrown straight up into the air from the ground with a speed of 10 m/s. What is the maximum height the ball will reach
    7·1 answer
  • PLEASE HELP!!!!
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!