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postnew [5]
2 years ago
5

Question 3(Multiple Choice Worth 3 points)

Physics
1 answer:
Burka [1]2 years ago
8 0

The unit of measurement used in the metric system is  Meters.

The metric system makes use of measurements that we often see every day. these are used to measure length, weight, and capability. you will often see these as grams, kilograms, millimetres, centimeters, meters, milliliters, and liters. The metric machine is used all around the globe as it is easy to understand.

The metric system is a system of measurement that succeeded the decimalized system primarily based on the meter that had been added in France in the 1790s.

Metrics are measures of quantitative assessment normally used for comparing and tracking performance or manufacturing. Metrics may be used in a ramification of situations. Metrics are heavily trusted in the monetary evaluation of corporations with the aid of each inner manager and external stakeholders.

Learn more about the metric system here:-brainly.com/question/1837503

#SPJ9

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 (a) How long can you rapidly climb stairs (116/min) on the 166.0 kcal of energy in a 200g apple? (b) How many flights is this
adoni [48]

Answer:

a) It will take you 16.94 min to climb the stairs.

b) The numbers of flights are 123 flights.

Explanation:

a) Let the energy consumption while climbing the stairs be 685 W in kcal/min is given by:

rate of energy consumption = (685 W)×[(0.01433kcal/min)/1 W]

                                               = 9.81605 kcal/min

the time it takes to climb the stairs is given by:

t = E/P

 = (166.0 kcal)/(9.8 kcal/min)

 = 16.94 min

Therefore, it will take you 16.94 min to climb the stairs.

b) Given t is the time it takes to climb stairs and N is the number of stairs to climb per min, then the number of stairs is:

n = t×N

  = (16.94)×(116)

  = 1965 stairs

given the number of stairs each flight as N1, then the number of flights is given by:

flights = n/N1

          = (1965)/(16)

          = 123 flights

Therefore, the numbers of flights are 123 flights.

7 0
4 years ago
What do a prism, a magnifying glass, a microscope, and eyeglasses ALL have in common? A) They are opaque. B) They refract light.
Elena L [17]
By definition, when the speed of the light changes when it passes from a material to another, this is called "Refraction of light". This happens when there is a difference in the index of refraction between both mediums o materials. Therefore, that speed depends of <span>the medium through  it passes. 
</span> 
 T<span>he index of refraction</span> is expressed as below: 
 n=c/v
 
 "n"  is <span>the index of refraction.
</span> "c" is <span>is the speed of light.
</span> "<span>v" is the phase velocity of light in the medium.
</span> 
 A prism, a magnifying glass, a microscope, and eyeglasses refract light. Therefore, the correct option is: B) They refract light.
6 0
3 years ago
Read 2 more answers
A solid cylinder is mounted above the ground with its axis of rotation oriented horizontally. A rope is wound around the cylinde
Romashka [77]

Answer:

(a)10.5 rad/s2

(b) 20.9 rev

(c) 47.27 m

Explanation:

As the block of mass 53 kg is falling and pulling on the rope. The tension force on the rope must be equal to the gravity acting on the block according to Newton's 3rd law

T = mg = 53*9.81 = 519.93  N

Since this tension force would rotate the cylinder freely without any friction. The torque created by this tension force is

To = TR = 519.93  * 0.36 = 187.17 Nm

This solid cylinder would have a moment of inertia around it's rotating axis of:

I = \frac{mR^2}{2} = \frac{275 * 0.36^2}{2} = 17.82kgm^2

(a)We can use Newton's 2nd law to calculate the angular acceleration exerted by such torque on the solid cylinder

\alpha = \frac{To}{I} = \frac{187.17}{17.82} = 10.5 rad/s^2

(b) With such constant angular acceleration, the angle it would make after 5s is

\theta = \frac{\alphat^2}{2} = \frac{10.5*5^2}{2} = 131.3 rad

Since each revolution equals to 2\pi rad of angle, we can calculate the number of revolution it makes

\frac{\theta}{2\pi} = \frac{131.3}{6.28} \approx 20.9 rev

(c) Assume the thickness of the rope is negligible (and its wounded radius is unchanging), we can calculate the rope length unwinded after rotating 131.3rad

\theta R = 131.3*0.36 = 47.27 m

3 0
3 years ago
A tennis ball hits with an initial velocity of 25 m/s [10 o above the
Sav [38]

First, calculate the components of its initial velocity v0:

v0x = v0cos10 = 24.6 m/s

v0y = v0sin10 = 4.34 m/s

The ball reaches its peak when vy = 0. Let's calculate the time it takes for vy to become zero:

vy = v0y - gt ---> t = v0y/g = 0.44 s

The horizontal distance it travels in this time is

x = v0xt = (24.6 m/s)(0.44 s)

= 10.8 m

Note that the net is 15 m away. After traveling a horizontal distance of 10.8 m, the height of the ball is

y = -(1/2)gt^2 + v0yt + 2.1

= -(4.9 m/s^2)(0.44 s)^2 + (4.34 m/s)(0.44 s) + 2.1 m

= -0.95 m + 1.9 m + 2.1 m

= 3.05 m

Note that this is the height of the ball at its peak. While the ball is well above the net at its peak, it is well short of its required horizontal distance to clear it. Instead, let's find the time it takes for the tennis ball to travel a horizontal distance of 15 m first:

x = v0xt ----> t = x/v0x = (15 m)/(24.6 m/s) = 0.61 s

Then calculate the height y when t = 0.61 s. If y > 0.9 m (height of the net), then the ball will clear the net.

y = -4.9t^2 + v0yt + 2.1

= -4.9(0.61 s)^2 + (4.34 m/s)(0.61 s) + 2.1 m

= -1.82 m + 2.65 m + 2.1 m

= 2.93 m

Yes, the ball will clear the net by 2.03 m.

3 0
3 years ago
g Let the orbital radius of a planet be R and let the orbital period of the planet be T. What quantity is constant for all plane
Wittaler [7]

Explanation:

Kepler's third law gives the relationship between the orbital radius and the orbital period of the planet. Its mathematical form is given by :

T^2=\dfrac{4\pi ^2}{GM}a^3

Here,

G is gravitational constant

M is mass of sun

It means that the mass of Sun is constant for all planets orbiting the sun, assuming circular orbits.

7 0
3 years ago
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